[REQ] [Swift5] Encode a user-defined model to Json when using multipart/form-data #8925
Description
Is your feature request related to a problem? Please describe.
When sending any user-defined models as multipart/form-data, Xcode could not build generated codes because of missing a method called encodeToJSON that is a member of JSONEncodable protocol.
Although existing primitive types conforms to this protocol, user-defined model does not.
For example, Xcode could not build this API.
openapi: 3.0.0
info:
title: test
version: '1.0'
servers:
- url: 'http://localhost:3000'
paths:
/postModel:
post:
summary: Create New User
operationId: post-user
responses:
'200':
description: User Created
content:
application/json:
schema:
$ref: '#/components/schemas/User'
examples: {}
'400':
description: Missing Required Information
description: Create a new user.
requestBody:
content:
multipart/form-data:
schema:
$ref: '#/components/schemas/Request'
parameters: []
components:
schemas:
User:
title: User
type: object
description: ''
x-examples: {}
properties:
integerValue:
type: integer
Request:
title: Request
type: object
properties:
user1:
$ref: '#/components/schemas/User'
Describe the solution you'd like
Implement encodeToJSON method for any user-defined models by protocol extension.
extension JSONEncodable where Self: Encodable {
func encodeToJSON() -> Any {
let encoder = JSONEncoder()
guard let data = try? encoder.encode(self) else {
fatalError("Could not encode to json: \(self)")
}
return data.base64EncodedString(options: Data.Base64EncodingOptions())
}
}Then, to confirm JSONEncodable for user-defined model, edit modelObject.mustache.
I already implement these codes and tested using 101da6e
If this request is acceptable, I will send PR.