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Bug #11149
closed
URI.parse keeps '?' for query and '#' for fragment even if they are empty
Description
p = URI.parse('http://example.com/path?query#fragment')
p.query = ''
p.fragment = ''
puts p.to_s
will output "http://example.com/path?#" but I think it should be "http://example.com/path" without '?' and '#'
Updated by naruse (Yui NARUSE) about 10 years ago
- Status changed from Open to Assigned
- Assignee set to naruse (Yui NARUSE)
As URL Standard, current behavior is correct.
https://url.spec.whatwg.org/
But Google Chrome's behavior is like what you say.
I keep watching how W3C/WHATWG decide this behavior.
Updated by davispuh (Dāvis Mosāns) about 10 years ago
Actually yes, I was wrong on this and it is expected behavior.
When one wants without '?' and '#' correct way is to set to nil and not to empty string ''
p.query = nil
p.fragment = nil
Updated by nobu (Nobuyoshi Nakada) over 7 years ago
At least, that test should not be in test_parse, but in test_set_component or others.
Updated by naruse (Yui NARUSE) about 7 years ago
- Status changed from Assigned to Rejected
Chrome also follows the behavior.
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