From: "marcandre (Marc-Andre Lafortune)" <ruby-core@...>
Date: 2013-02-18T12:21:41+09:00
Subject: [ruby-core:52427] [ruby-trunk - Bug #7842] An alias of a "prepend"ed method skips the original method when calling super


Issue #7842 has been updated by marcandre (Marc-Andre Lafortune).


phluid61 (Matthew Kerwin) wrote:
> I'm sorry, but this ticket confuses me. Why does "A" ever get output, if
>  B#m does not also call super?

You're right to be confused, there's a missing `super` in the examples that everyone assumed was there.

So here's the corrected version:

    module P
      def m; puts "P"; super; end
    end
    class A
      def m; puts "A"; end
    end
    class B < A
      def m; puts "B"; super; end
      alias m2 m
      prepend P
      alias m3 m
    end

    B.new.m2 #=> expected: B, A
    B.new.m3 #=> expected: P, B, A


----------------------------------------
Bug #7842: An alias of a "prepend"ed method skips the original method when calling super
https://bugs.ruby-lang.org/issues/7842#change-36484

Author: mame (Yusuke Endoh)
Status: Assigned
Priority: Normal
Assignee: matz (Yukihiro Matsumoto)
Category: 
Target version: next minor
ruby -v: ruby 2.0.0dev (2013-02-13 trunk 39225) [x86_64-linux]


Hello,

  module P
    def m; puts "P"; super; end
  end
  class A
    def m; puts "A"; end
  end
  class B < A
    def m; puts "B"; end
    prepend P
    alias m2 m
  end
  B.new.m2
    #=> expected: P, B, A
    #=> actual:   P, A

Is this intentional?
It looks weird to me that calling super of P#m (as m2) skips A#m.

-- 
Yusuke Endoh <mame@tsg.ne.jp>


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