From: wolf@... Date: 2018-03-04T23:18:44+00:00 Subject: [ruby-core:85923] [Ruby trunk Feature#4824] Provide method Kernel#executed? Issue #4824 has been updated by graywolf (Gray Wolf). dsferreira (Daniel Ferreira) wrote: > [..] > > Usually when we use > > ```ruby > if __FILE__ == $0 > # call code to be run > main(ARGV) > end > ``` > > We are saying that the code should only be executed if the condition applies. > > [..] Exactly, and the condition is: *was this file directly* **executed?**. I mean, I get what you mean, but still think it's confusing. ---------------------------------------- Feature #4824: Provide method Kernel#executed? https://bugs.ruby-lang.org/issues/4824#change-70778 * Author: lazaridis.com (Lazaridis Ilias) * Status: Assigned * Priority: Normal * Assignee: matz (Yukihiro Matsumoto) * Target version: ---------------------------------------- The current construct to execute main code looks not very elegant: ~~~ruby if __FILE__ == $0 my_main() # call any method or execute any code end ~~~ With a `Kernel#executed?` method, this would become more elegant: ~~~ruby if executed? #do this #do that my_main() end ~~~ or ~~~ruby main() if executed? ~~~ This addition would not break any existent behaviour. -- https://bugs.ruby-lang.org/ Unsubscribe: