From: usa@... Date: 2018-03-18T14:58:12+00:00 Subject: [ruby-core:86182] [Ruby trunk Bug#13736] ruby -00 should be the same as setting $/="" Issue #13736 has been updated by usa (Usaku NAKAMURA). Backport changed from 2.2: REQUIRED, 2.3: REQUIRED, 2.4: DONE to 2.2: REQUIRED, 2.3: DONE, 2.4: DONE ruby_2_3 r62817 merged revision(s) 59970. ---------------------------------------- Bug #13736: ruby -00 should be the same as setting $/="" https://bugs.ruby-lang.org/issues/13736#change-71068 * Author: dawg (Andrew Dumke) * Status: Closed * Priority: Normal * Assignee: matz (Yukihiro Matsumoto) * Target version: * ruby -v: 2.4.1p111 * Backport: 2.2: REQUIRED, 2.3: DONE, 2.4: DONE ---------------------------------------- Suppose you have blocks of text separated by 2 or more \n. A typical text file with records defined by a black line. Given: ``` $ cat lines f1, r1 f2, r1 then 2 \n: f1, r2 then 3 \n: f1,r3 f2,r3 then 4 \n: f1, r4 f2,r4 then 6 \n: f1,r5 ``` The script `$ ruby -00 -F"\n" -lane 'END{p $.}' lines` SHOULD have the same number of records as `$ ruby -F"\n" -lane 'BEGIN{$/=""}; END{p $.}' lines`. It does not not. The script `$ ruby -00 -F"\n" -lane 'END{p $.}' lines` SHOULD have the same number of record as `$ perl -00 -F"\n" -lane 'END{print $.}' lines` Again, it does not. The script `$ ruby -00 -F"\n" -lane 'END{p $.}' lines` shows 8. The other scripts here show 5 -- the correct number. The behavior of the `-00` command switch is not the same as perl's `-00` command switch. It is also not the same as setting `$/=""` in either ruby or perl. The `\n\n` pattern between blocks should be a single record separator even if you have `\n\n\n\n\n` That is true in perl, awk, gawk, and ruby with `$/=""`. It is not true with `ruby -00`. This is a bug. ---Files-------------------------------- ruby_bug.sh (1.39 KB) -- https://bugs.ruby-lang.org/ Unsubscribe: