ou are given two positive integers, a and b (a<b ). For some positive integer n , two players will play a game starting with a pile of n stones. They take turns removing exactly a or exactly b stones from the pile. The player who is unable to make a move loses. Find a positive integer n such that the second player to move in this game has a winning strategy. This means that no matter what moves the first player makes, the second player can carefully choose their moves (possibly depending on the first player's moves) to ensure they win. Input Each test contains multiple test cases. The first line contains the number of test cases t (1≤t≤100 ). The description of the test cases follows. The only line of each test case contains two integers, a and b (1≤a<b≤100 ). Output For each test case, output any positive integer n (1≤n≤106 ) such that the second player to move wins. It can be proven that such an n always exists under the constraints of the problem. 请帮我编写一个C++代码
时间: 2024-04-11 22:29:01 浏览: 195
Sure! Here's a C++ code snippet that solves the given problem:
```cpp
#include <iostream>
int main() {
int t;
std::cin >> t;
while (t--) {
int a, b;
std::cin >> a >> b;
// Choose n as a multiple of (b-a) to ensure the second player wins
int n = b - a;
std::cout << n << std::endl;
}
return 0;
}
```
This code reads the number of test cases `t`, and for each test case, it reads the values of `a` and `b`. Then, it calculates `n` as the difference between `b` and `a` and outputs it.
Note: The problem states that any positive integer `n` such that `(1≤n≤106)` can be chosen. The code above chooses `n` as `(b-a)`, but you can choose any other positive integer within the given constraints.
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