数据库中的复数运算与临时表使用
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发布时间: 2025-08-24 00:05:58 阅读量: 1 订阅数: 5 

### 数据库中的复数运算与临时表使用
#### 1. 复数除法的用户自定义函数实现
我们可以创建一个名为 `dbo.cxDivide` 的用户自定义函数来实现复数除法。该函数依据公式计算结果复数的实部和虚部,具体代码如下:
```sql
CREATE FUNCTION dbo.cxDivide(
@cx1 as complex,
@cx2 as complex)
RETURNS complex
AS
BEGIN
IF dbo.cxValid(@cx1) = 0 OR dbo.cxValid(@cx2) = 0
RETURN NULL
DECLARE
@a1 AS decimal(19,9),
@b1 AS decimal(19,9),
@a2 AS decimal(19,9),
@b2 AS decimal(19,9)
DECLARE
@real AS decimal(19,9),
@imaginary AS decimal(19,9)
SET @a1 = dbo.cxGetReal(@cx1)
SET @a2 = dbo.cxGetReal(@cx2)
SET @b1 = dbo.cxGetImaginary(@cx1)
SET @b2 = dbo.cxGetImaginary(@cx2)
-- ((a1*a2 + b1*b2)/(a2*a2 + b2*b2)) + ((a2*b1 - a1*b2)/(a2*a2 + b2*b2))i
SET @real = (@a1*@a2 + @b1*@b2)/(@a2*@a2 + @b2*@b2)
SET @imaginary = (@a2*@b1 - @a1*@b2)/(@a2*@a2 + @b2*@b2)
RETURN dbo.cxStrForm(@real, @imaginary)
END
GO
```
#### 2. 复数的极坐标形式与向量大小计算
复数还可以用极坐标形式 `(r, θ)` 表示。其中,`r` 是向量的大小,即复平面上原点到点 `(a, b)` 的距离;`θ` 是实轴与表示复数的向量之间的夹角。
可以使用勾股定理计算复数向量的大小,公式为 `r = SQRT(a^2 + b^2)`。以下是实现该计算的用户自定义函数 `dbo.cxVectorSize`:
```sql
CREATE FUNCTION dbo.cxVectorSize(
@cx as complex)
RETURNS decimal(19,9)
AS
BEGIN
IF dbo.cxValid(@cx) = 0
RETURN NULL
DECLARE
@real AS decimal(19,9),
@imaginary AS decimal(19,9)
SET @real = dbo.cxGetReal(@cx)
SET @imaginary = dbo.cxGetImaginary(@cx)
-- r = SQRT(a^2 + b^2)
RETURN SQRT(@real*@real + @imaginary*@imaginary)
END
GO
```
#### 3. 复数函数的使用
为了测试复数函数,我们可以创建一个简单的表 `T1` 来存储复数,并对该表执行一些查询。
```sql
CREATE TABLE T1
(
key_col int NOT NULL PRIMARY KEY,
cx1 complex NOT NULL,
cx2 complex NOT NULL
)
INSERT INTO T1 VALUES(1, '5 + 2i', '2 + 4i')
INSERT INTO T1 VALUES(2, '2 + 9i', '4 + 5i')
INSERT INTO T1 VALUES(3, '7 + 4i', '3 + 2i')
INSERT INTO T1 VALUES(4, '3 + 2i', '6 + 3i')
INSERT INTO T1 VALUES(5, '4 + 3i', '7 + 2i')
INSERT INTO T1 VALUES(6, '1 + 4i', '4 + 3i')
INSERT INTO T1 VALUES(7, '7 + 2i', '8 + 1i')
INSERT INTO T1 VALUES(8, '2 + 3i', '3 + 6i')
INSERT INTO T1 VALUES(9, '3 + 6i', '2 + 8i')
INSERT INTO T1 VALUES(10, '2 + 1i', '3 + 2i')
```
以下查询展示了如何在查询中嵌入复数函数进行加法、减法、乘法和除法运算:
```sql
SELECT
key_col,
cx1,
cx2,
dbo.cxAdd(cx1, cx2) AS cxAdd,
dbo.cxSubtract(cx1, cx2) AS cxSubtract,
dbo.cxMult(cx1, cx2) AS cxMult,
dbo.cxDivide(cx1, cx2) AS cxDivide
FROM
T1
```
运算结果如下表所示:
| key_col | cx1 | cx2 | cxAdd | cxSubtract | cxMultiply | cxDivide |
| ---- | ---- | ---- | ---- | ---- | ---- | ---- |
| 1 | 5 + 2i | 2 + 4i | 7 + 6i | 3 - 2i | 2 + 24i | 0.9 - 0.8i |
| 2 | 2 + 9i | 4 + 5i | 6 + 14i | 2 + 4i | 37 + 46i | 1.29268292 + 0.63414634i |
| 3 | 7 + 4i | 3 + 2i | 10 + 6i | 4 + 2i | 13 + 26i | 2.2307
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