Given binary number is (1101011)2.
(11001)2 = (1 × 26) + (1 × 25) + (0 × 24) + (1 × 23) + (0 × 22) + (1 × 21) + (1 × 20)
= 64 + 32 + 0 + 8 + 0 + 2 + 1 = 107
Therefore, the binary number (1101011)2 is equal to the decimal number (107)10.
To convert the (39)10 into a binary number, we have to divide 39 continuously by 2 until we obtain the quotient of 1.
Thus, (39)10 in the binary number system is (100111)2.
Method 1:
Step 1: Starting at the right end, divide the given binary number into a pair of three digits.
 10-110-110
Step 2: We can notice that the first group doesn't have three digits. So add zeros on the left. Now, substitute the value of the octal number into it.
010-110-110
(010)2 = (2)8
(110)2 = (6)8
(110)2 = (6)8
Step 3: Now, combine all digits.
010-110-110 = 2-6-6 = 266
Therefore, the binary number (10110110)2 in the octal system is 266.
Method 2:
It is a long process as we have to perform two conversions, i.e., from binary to decimal and again from decimal to octal.
Step 1: Converting the binary number (10110110)2 to decimal
(1 × 27) + (0 × 26) + (1 × 25) + (1 × 24) + (0 × 23) + (1 × 22) + (1 × 21) + (0 × 20)
= 128 + 0 + 32 + 16 + 0 + 4 + 2 + 0 = (182)10
Step 2: Now, divide the obtained decimal number 8.
Therefore, the binary number (10110110)2 in the octal system is 266.
Method 1:
Step 1: Starting at the right end, divide the given binary number into a pair of four digits.
1101010 ⇒ 110-1010
Step 2: We can notice that the first group doesn't have four digits. So add zeros on the left. Now, substitute the value of the hexadecimal number into it.
110-1010 ⇒ 0110-1010
(0110)2 = (6)16
(1010)2 = (A)16
Step 3: Now, combine all digits.
0110-1010 = 6 - A = (6A)16
Thus, the binary number (1101010)2 in the hexadecimal system is 6A.
Method 2:
It is a long process as we have to perform two conversions, i.e., from binary to decimal and again from decimal to hexadecimal.
Step 1: Converting the binary number (1101010)2 Â to decimal
(1 × 26) + (1 × 25) + (0 × 24) + (1 × 23) + (0 × 22) + (1 × 21) + (0 × 20)
= 64 + 32 + 0 + 8 + 0 + 2 + 0 = (106)10
Step 2: Â Now, divide the obtained decimal number by 16.
We know that in the hexadecimal system 10 is equal to A. Thus, the hexadecimal number is 6A.
Therefore, the binary number (1101010)2 in the hexadecimal system is 6A.
To convert the (73)10 into a binary number, we have to divide it continuously by 2 until we obtain the quotient of 1.
Thus, (73)10 in the binary number system is (1001001)2.
To convert the binary number into octal, first, we have to divide the given binary number into a pair of three digits, starting from the right end. Now, substitute the value of the octal number into it.
110010101 ⇒ 110 - 010 - 101
6 - 2 - 5 = 625
Therefore, the binary number (110010101)2 in the octal system is 625.
To convert the binary number into hexadecimal, we first have to divide the given binary number into a pair of four digits, starting from the right end. Now, substitute the value of the hexadecimal number into it.
10110110 ⇒ 1011 - 0110
(1011)2 = (B)16
(0110)2 = (6)16
So, (10110110)2 = (B6)16
Therefore, the binary number (10110110)2 in the hexadecimal system is B6.