How to pass an array as a function parameter in JavaScript?

Here are different ways to pass an array as a function paramter in JavaScript.

1. Using apply() Method

The apply() method invokes a function with a specified `this` value and an array of arguments. It takes two parameters: the first is the `this` context for the function, and the second is an array of arguments. This allows calling the function with those arguments.

function unmodifiableFunction(a, b, c) {
    console.log(`First value is: ${a} 
Second value is: ${b} 
Third value is:  ${c}`)
}

arrayToPass = [1, "Two", 3];
unmodifiableFunction.apply(null, arrayToPass);

First value is: 1 
Second value is: Two 
Third value is:  3

2. Using Spread Operator

The spread operator is used in places where zero or more arguments are expected. It can be used with iterators that expand in a place where there may not be a fixed number of expected arguments (like function parameters). The required function is called as given the arguments array using the spread syntax so that it would fill in the arguments of the function from the array. 

function unmodifiableFunction(a, b, c) {
    console.log(`First value is: ${a}
Second value is: ${b}
Third value is:  ${c}`)
}

arrayToPass = [1, "Two", 3];
unmodifiableFunction(...arrayToPass);

First value is: 1
Second value is: Two
Third value is:  3

3. Using call() Method

The call() method calls a function with a given this value and arguments provided individually. This method allows you to explicitly specify the this context and the arguments separately. To pass an array as arguments, you can use the spread syntax to expand the array elements as individual arguments.

function unmodifiableFunction(a, b, c) {
    console.log(`First value is: ${a}
Second value is: ${b}
Third value is:  ${c}`);
}

let arrayToPass = [1, "Two", 3];
unmodifiableFunction.call(null, ...arrayToPass);

First value is: 1
Second value is: Two
Third value is:  3