Implement rand12() using rand6() in one line Last Updated : 08 Jul, 2024 Comments Improve Suggest changes Like Article Like Report Given a function, rand6() that returns random numbers from 1 to 6 with equal probability, implement the one-liner function rand12() using rand6() which returns random numbers from 1 to 12 with equal probability. The solution should minimize the number of calls to the rand6() method. Use of any other library function and floating point arithmetic are not allowed. The idea is to use expression rand6() + (rand6() % 2) * 6. It returns random numbers from 1 to 12 with equal probability. The expression is equivalent to - // if rand6() is even if (rand6() % 2) return 6 + rand6(); else // if rand6() is odd return rand6(); We can also use any one of the below expressions that works in a similar way - rand6() + !(rand6() % 2) * 6 orrand6() + (rand6() & 1) * 6 orrand6() + !(rand6() & 1) * 6Below is the implementation of the above approach: C++ #include <cstdlib> // for rand and srand #include <ctime> // for time #include <iostream> using namespace std; // Function that returns random numbers from 1 to 6 with // equal probability int rand6() { // rand() will generate random numbers between 0 and // RAND_MAX with equal probability rand() % 6 returns // number from 0 to 5 with equal probability (rand() % // 6) + 1 returns number from 1 to 6 with equal // probability return (rand() % 6) + 1; } // The function uses rand6() to return random numbers from 1 // to 12 with equal probability int rand12() { return rand6() + (rand6() % 2) * 6; } // Driver code to test above functions int main() { // Initialize random number generator srand(time(NULL)); int N = 12; int freq[N + 1] = { 0 }; // call rand12() multiple times and store its results for (int i = 0; i < N * 100000; i++) freq[rand12()]++; // print frequency of numbers 1-12 for (int i = 1; i <= N; i++) cout << freq[i] << " "; return 0; } Java import java.util.Random; public class RandomNumbers { public static int rand6() { Random random = new Random(); //nextInt(6) generates a random number from 0 to 5 return random.nextInt(6) + 1; } public static int rand12() { return rand6() + (rand6() % 2) * 6; } public static void main(String[] args) { int N = 12; int[] freq = new int[N + 1]; // Initialize random number generator Random random = new Random(); // Call rand12() multiple times and store its results for (int i = 0; i < N * 100000; i++) { freq[rand12()]++; } // Print the frequency of numbers 1-12 for (int i = 1; i <= N; i++) { System.out.print(freq[i] + " "); } } } Python import random # Create a single instance of Random for better performance rand = random.Random() # Function that returns random numbers from 1 to 6 with equal probability def rand6(): return rand.randint(1, 6) # The function uses rand6() to return random numbers from 1 to 12 with equal probability def rand12(): return rand6() + (rand6() % 2) * 6 # Driver code to test above functions if __name__ == "__main__": N = 12 iterations = 100000 freq = [0] * (N + 1) # call rand12() multiple times and store its results for _ in range(iterations): freq[rand12()] += 1 # print frequency of numbers 1-12 for i in range(1, N + 1): print freq[i], # Wait for user input to keep the console window open try: raw_input("Press Enter to exit") except EOFError: pass C# using System; class Program { // Create a single instance of Random for better performance static Random rand = new Random(); // Function that returns random numbers from 1 to 6 with equal probability static int Rand6() { return rand.Next(1, 7); } // The function uses Rand6() to return random numbers from 1 to 12 with equal probability static int Rand12() { return Rand6() + (Rand6() % 2) * 6; } // Driver code to test above functions static void Main() { int N = 12; int iterations = 100000; int[] freq = new int[N + 1]; // call Rand12() multiple times and store its results for (int i = 0; i < iterations; i++) freq[Rand12()]++; // print frequency of numbers 1-12 for (int i = 1; i <= N; i++) Console.Write(freq[i] + " "); Console.ReadLine(); // Added to keep the console window open until a key is pressed } } JavaScript function rand6() { // Generates a random number from 1 to 6 return Math.floor(Math.random() * 6) + 1; } function rand12() { return rand6() + (rand6() % 2) * 6; } const N = 12; const freq = new Array(N + 1).fill(0); // Call rand12() multiple times and store its results for (let i = 0; i < N * 100000; i++) { freq[rand12()]++; } // Print the frequency of numbers 1-12 for (let i = 1; i <= N; i++) { console.log(freq[i]); } Output: 100237 100202 99678 99867 100253 99929 100287 100449 99827 99298 100019 99954 Another Solution:int rand12() { return (rand6() * 2) - (rand6() & 1); }rand6() * 2: This will return even numbers 2, 4, 6, 8, 10 and 12 with equal probability and rand6() & 1: This will return 0 or 1 based on rand6() is even or odd respectively. So, the expression (rand6() * 2) - (rand6() & 1): This will return random numbers from 1 to 12 with equal probability. Below is the implementation of the above approach: C++ #include <cstdlib> #include <ctime> #include <iostream> // Assume rand6 generates a random integer between 1 and 6 int rand6() { return rand() % 6 + 1; } int rand12() { return (rand6() * 2) - (rand6() & 1); } int main() { // Seed the random number generator srand(time(0)); // Generate a random number between 1 and 12 int randomNum = rand12(); // Print the random number std::cout << "Random number between 1 and 12: " << randomNum << std::endl; return 0; } Java import java.util.Random; public class Main { private static final Random rand = new Random(); // Assume rand6 generates a random integer between 1 and 6 public static int rand6() { return rand.nextInt(6) + 1; } public static int rand12() { return (rand6() * 2) - (rand6() & 1); } public static void main(String[] args) { // Generate a random number between 1 and 12 int randomNum = rand12(); // Print the random number System.out.println("Random number between 1 and 12: " + randomNum); } } Python import random def rand6(): """ Generates a random integer between 1 and 6, inclusive. Returns: int: A random integer between 1 and 6. """ return random.randint(1, 6) def rand12(): """ Generates a random integer between 1 and 12, inclusive. Returns: int: A random integer between 1 and 12. """ # Generate two random numbers between 1 and 6 num1 = rand6() num2 = rand6() # Calculate the result using the formula: (2 * num1) - (num2 & 1) result = (2 * num1) - (num2 & 1) # Ensure the result is within the range of 1 to 12 if result > 12: result = result % 12 return result if __name__ == "__main__": # Seed the random number generator random.seed() # Generate a random number between 1 and 12 random_num = rand12() # Print the random number print("Random number between 1 and 12:", random_num) JavaScript /** * Generates a random integer between 1 and 6, inclusive. * * @returns {number} A random integer between 1 and 6. */ function rand6() { return Math.floor(Math.random() * 6) + 1; } /** * Generates a random integer between 1 and 12, inclusive. * * @returns {number} A random integer between 1 and 12. */ function rand12() { // Generate two random numbers between 1 and 6 let num1 = rand6(); let num2 = rand6(); // Calculate the result using the formula: (2 * num1) - (num2 & 1) let result = (2 * num1) - (num2 % 2); // Ensure the result is within the range of 1 to 12 if (result > 12) { result = result % 12; if (result === 0) { result = 12; } } return result; } // Generate a random number between 1 and 12 let randomNum = rand12(); // Print the random number console.log("Random number between 1 and 12:", randomNum); OutputRandom number between 1 and 12: 7 Comment More infoAdvertise with us Next Article Generate integer from 1 to 7 with equal probability A Aditya Goel Improve Article Tags : Randomized DSA Similar Reads Randomized Algorithms Randomized algorithms in data structures and algorithms (DSA) are algorithms that use randomness in their computations to achieve a desired outcome. 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