Logarithmic Functions Practice Problems
Last Updated :
30 Jul, 2024
Logarithmic Functions Practice Problems help students grasp the concept of logarithms through hands-on exercises and examples. These problems are designed to deepen understanding and proficiency in applying logarithmic functions in various mathematical contexts.
Logarithmic functions are essential in mathematics for simplifying exponential equations. The basic logarithmic function is logex where e is the base of the logarithmic function. Logarithmic functions are the reverse function of exponentiation. In this article, we will examine the important formulas for logarithmic functions and logarithmic function practice problems.
What are Logarithmic Functions?
A logarithmic function is the inverse of an exponential function. It is typically written in the form
y = logb(x)
where b is the base of the logarithm, x is the argument, and y is the result. This means by = x.
The table below represents the important formulas for Logarithmic Functions.
Logarithmic Functions Practice Problems - Solved
These solved Logarithmic Functions Practice Problems will help you understand the concept and use them in a better manner.
1. Solve log10 x = 3.
log10 x = 3
Using the logarithm definition logax = p ⇔ x = ap
x = 103
x = 1000
2. Evaluate y = log35 + log34
y = log35 + log34
Using logarithmic function property
log(ab) = log a + log b
y = log3(5 × 4)
y = log320
3. Solve log5x + 20 = 22
log5x + 20 = 22
log5x = 22 - 20
log5x = 2
Using property logax = p ⇔ x = ap
x = 52
x = 25
4. Solve z = log7 49 - log77
z = log7 49 - log77
Using property: loga a = 1
z = log7 72 - 1
Using property: log ab = b log a
z = 2 log7 7 - 1
Using property: loga a = 1
z = 2 - 1
z = 1
5. Evaluate p = log618 - log63
p = log618 - log63
Using property log(a/b) = log a - log b
p = log6 (18 / 3)
p = log66
Using property: loga a = 1
p = 1
6. Evaluate log3(6x) = 2
log3(6x) = 2
Using property logax = p ⇔ x = ap
6x = 32
6x = 9
x = 3/2
7. Solve log4(16x - x2) = 3
log4(16x - x2) = 3
Using property logax = p ⇔ x = ap
(16x - x2) = 43
(16x - x2) = 64
x2 - 16x + 64 = 0
(x - 8)2 = 0
x = 8
8. Solve c = log927.
c = log927
Using property: logba = logxa / logxb
c = log327 / log39
c = log333 / log332
c = (3log33) / (2log33)
Using property: loga a = 1
c = 3/2
9. Find the value of x when log2x + log2(x + 6) = 4.
log2x + log2(x + 6) = 4
Using formula: logb (pq) = logb p + logb q
log2 [x (x + 6)] = 4
Using formula: ax = p ⇔ x = logap
[x (x + 6)] = 24
[x (x + 6)] = 16
x2 + 6x – 16 = 0
x = 2 or – 8
10. Find the domain and range of given logarithmic function y = log (5x – 25) + 7.
y = log (5x – 25) + 7
To find the domain of the given function put 5x – 25 > 0
5x – 25 > 0
5x > 25
x > 5
Domain of the given logarithmic function = (5, ∞)
We know that,
Range of any logarithmic function is set of all real numbers.
Logarithmic Functions Practice Problems - Unsolved
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