Print a character n times without using loop, recursion or goto in C++

Given a character c and a number n, print the character c, n times. We are not allowed to use loop, recursion, and goto. Examples :

Input : n = 10, c = 'a'
Output : aaaaaaaaaa

Input : n = 6, character = '@'
Output : @@@@@@

In C++, there is a way to initialize a string with a value. It can be used to print a character as many times as we want. While declaring a string, it can be initialized by using the feature provided by C++. It takes 2 arguments. First is the number of times we want to print a particular character and the other is the character itself.

Below is the implementation which illustrates this. 

// CPP Program to print a character 
// n times without using loop,
// recursion or goto
#include<bits/stdc++.h>
using namespace std;

// print function
void printNTimes(char c, int n)
{
    // character c will be printed n times
    cout << string(n, c) << endl;
}

// driver code
int main()
{
    // no of times a character
    // need to be printed
    int n = 6;
    char c = 'G';
    
    // function calling
    printNTimes(c, n);

    return 0; 
}

GGGGGG

Time Complexity: O(1)
Auxiliary Space: O(1)

Another Method: As we know that every time an object of a class is created the constructor of that class is called we can use it to our advantage and print the character inside the constructor, and create N objects of that class. 

#include<bits/stdc++.h>
using namespace std;

class Geeks{

    public:
        Geeks(){
            cout<<"@ ";
        }
        
};

int main(){
    int N =6;

    Geeks obj[N];
    return 0;
}

@ @ @ @ @ @ 

Time Complexity: O(1)
Auxiliary Space: O(1)