Python Program to Get Sum of N Armstrong Number

# Function to calculate order of the number
def order(x):
    # returns the length of the number
    return len(str(x))

# Function to check whether the given number is
# Armstrong number or not


def isArmstrong(x):
    k = order(x)  # order of the number
    cur = x
    sum1 = 0
    while (cur != 0):
        # For every digit r in the current number, compute r**k.
        r = cur % 10
        sum1 = sum1 + int(r**k)
        cur = cur//10
# If sum of all such values is equal to the current number
# then add that element to result.
    return (sum1 == x)

# Python program to determine the sum of
# first n armstrong numbers


def getSumOfArmstrong(n):
    cur = 1
    result = 0
    cur_elems = 0  
    # numbers found so far.
    while cur_elems != n:  
        if isArmstrong(cur):  
            result += cur 
            cur_elems += 1
        cur += 1
    return result


print(getSumOfArmstrong(11))

# Function to calculate order of the number
def order(x):
    # Increments the length by 1 for
    # current units digit and finds
    # orders for remaining digits.
    if x//10 == 0:
        return 1
# returns the length of the number
    return 1+order(x//10)


# Function to check whether the given number is
# Armstrong number or not
def isArmstrong(x, order):
    if x == 0:
        return 0
    if x != 0:
        # digit present in the units place raised
        # to the order of number and calls the
        # function again for remaining digits
        # excluding the units digit.
        return int(pow(x % 10, order))+isArmstrong(x//10, order)

# Python program to determine the sum of
# first n armstrong numbers


def getSumOfArmstrong(n):
    cur = 1
    result = 0  # Variable to store final result
    cur_elems = 0  # Variable to count total number of Armstrong
    # numbers found so far.
    while cur_elems != n:  # Iterating until we get n armstrong numbers
        # Checking current number armstrong is or not.
        if isArmstrong(cur, order(cur)) == cur:
            result += cur  # Storing sum of Armstrong numbers.
            cur_elems += 1
        cur += 1
    return result


print(getSumOfArmstrong(11))