PYGLET – Loading Program Resource

Last Updated : 05 Aug, 2021

In this article we will see how we can load a program resource in PYGLET module in python. Pyglet is easy to use but powerful library for developing visually rich GUI applications like games, multimedia etc. A window is a "heavyweight" object occupying operating system resources. Windows may appear as floating regions or can be set to fill an entire screen (fullscreen). In order to load a file i.e resource we use resource module of pyglet. This module allows applications to specify a search path for resources. Relative paths are taken to be relative to the application’s __main__ module. ZIP files can appear on the path; they will be searched inside. Loader load program resource files from disk. The loader contains a search path which can include filesystem directories, ZIP archives and Python packages.
We can create a window object with the help of command given below

# creating a window
window = pyglet.window.Window(width, height, title)

In order to create window we use Loader method with the pyglet.resource
Syntax : resource.Loader(path)
Argument : It takes resource path i.e string as argument
Return : It returns Loader object

Below is the implementation

Python3

# importing pyglet module 
import pyglet 
import pyglet.window.key as key
  
# width of window 
width = 500
  
# height of window 
height = 500
  
# caption i.e title of the window 
title = "Geeksforgeeks"
  
# creating a window 
window = pyglet.window.Window(width, height, title) 
  
# text  
text = "Welcome to GeeksforGeeks"
 
# creating label with following properties
# font = cooper
# position = 250, 150
# anchor position = center
label = pyglet.text.Label(text, 
                          font_name ='Cooper', 
                          font_size = 16, 
                          x = 250,  
                          y = 150, 
                          anchor_x ='center',  
                          anchor_y ='center')


# creating a batch 
batch = pyglet.graphics.Batch()

# loading geeksforgeeks image
image = pyglet.image.load('gfg.png')


# creating sprite object
# it is instance of an image displayed on-screen
sprite = pyglet.sprite.Sprite(image, x = 200, y = 230)
  
# on draw event 
@window.event 
def on_draw(): 
      
    # clear the window 
    window.clear() 
      
    # draw the label
    label.draw() 
    
    # draw the image on screen
    sprite.draw()
      
# key press event     
@window.event 
def on_key_press(symbol, modifier): 
  
    # key "C" get press 
    if symbol == key.C: 
        
        # printing the message
        print("Key : C is pressed")
        
# image for icon 
img = image = pyglet.resource.image("gfg.png") 

# setting image as icon 
window.set_icon(img) 

# loading a file i.e program resource
value = pyglet.resource.Loader("E:/btech / certi / gfg.jpg")

# showing value with the help of label
label.text = str(value)
   
# start running the application 
pyglet.app.run()