Scraping And Finding Ordered Words In A Dictionary using Python Last Updated : 10 Apr, 2025 Comments Improve Suggest changes Like Article Like Report What are ordered words? An ordered word is a word in which the letters appear in alphabetic order. For example abbey & dirt. The rest of the words are unordered for example geeksThe task at hand This task is taken from Rosetta Code and it is not as mundane as it sounds from the above description. To get a large number of words we will use an online dictionary available on http://www.puzzlers.org/pub/wordlists/unixdict.txt which has a collection of about 2,500 words and since we are gonna be using python we can do that by scraping the dictionary instead of downloading it as a text file and then doing some file handling operations on it. Requirements: pip install requestsCode The approach will be to traverse the whole word and compare the ascii values of elements in pairs until we find a false result otherwise the word will be ordered. So this task will be divided in 2 parts: ScrapingUsing the python library requests we will fetch the data from the given URLStore the content fetched from the URL as a stringDecoding the content which is usually encoded on the web using UTF-8Converting the long string of content into a list of wordsFinding the ordered wordsTraversing the list of wordsPairwise comparison of the ASCII value of every adjacent character in each wordStoring a false result if a pair is unorderedOtherwise printing the ordered word Python # Python program to find ordered words import requests # Scrapes the words from the URL below and stores # them in a list def getWords(): # contains about 2500 words url = "http://www.puzzlers.org/pub/wordlists/unixdict.txt" fetchData = requests.get(url) # extracts the content of the webpage wordList = fetchData.content # decodes the UTF-8 encoded text and splits the # string to turn it into a list of words wordList = wordList.decode("utf-8").split() return wordList # function to determine whether a word is ordered or not def isOrdered(): # fetching the wordList collection = getWords() # since the first few of the elements of the # dictionary are numbers, getting rid of those # numbers by slicing off the first 17 elements collection = collection[16:] word = '' for word in collection: result = 'Word is ordered' i = 0 l = len(word) - 1 if (len(word) < 3): # skips the 1 and 2 lettered strings continue # traverses through all characters of the word in pairs while i < l: if (ord(word[i]) > ord(word[i+1])): result = 'Word is not ordered' break else: i += 1 # only printing the ordered words if (result == 'Word is ordered'): print(word,': ',result) # execute isOrdered() function if __name__ == '__main__': isOrdered() Output:aau: Word is orderedabbe: Word is orderedabbey: Word is orderedabbot: Word is orderedabbott: Word is orderedabc: Word is orderedabe: Word is orderedabel: Word is orderedabet: Word is orderedabo: Word is orderedabort: Word is orderedaccent: Word is orderedaccept: Word is ordered................................................................................. 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