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![0, 2.68 3.64 3.70 4.60 3.62 4.84 5.74
10 10 10 10 10 10 10
0
2.68 3.64
3.70 4.60
3.62
4.84 5.74
Simpson rule
Area1 = d/3(o1+07)+4(o2+o4+o6)+2(03+o5)
10/3 [ 0+4.84+4(2.68+3.70+3.62)+2(3.64+4.60)]
= 204.4m2
Area2 = 10/2(4.84+5.74) = 52.9m2
Total area = 204.4+52.9 = 257.3m2
Trapezoidal rule
Area = d[(o1+on)/2 +o2+o3+o4……on-1]
= 10 [ (0+5.74)/2 + 2.68+3.64+3.70+4.60+3.62+4.84]
= 259.5m2](https://image.slidesharecdn.com/areacalculations-220825071247-4ab6b2f8/75/area-calculations-pptx-1-2048.jpg)
![D = 5
Ordinates
O1 2.72
02 3.46
O3 5.23
O4 6.80
O5 4.86
O6 3.35
07 3.00
08 2.50
09 1.60
o1 o9
Trapezoidal rule
A = 5[(2.72+1.60)/2+3.46+5.23+6.80+4.86+3.35+3+2.50]
= 156.8m2
Simpsons rule
A = 5/3[ (2.72+1.60) +4(3.46+6.80+3.35+2.50)+2(5.23+4.86+3)
= 158.23m2](https://image.slidesharecdn.com/areacalculations-220825071247-4ab6b2f8/75/area-calculations-pptx-2-2048.jpg)
![2.10 3.15 4.50 3.60 4.58 7.85 6.45 4.65 3.14
Trapezoidal Rule
A = d[ (o1+on)/2 + o2+o3+o4……on-1]
= 10[ (0+5.74)/2 + 2.68+3.64+3.7+4.6+3.62+4.84]
= 259.5m2
0
2.68
3.64
3.70
4.60
3.62
4.84
5.74
D= 10m
2.68
3.64
3.70
4.60 3.62
4.84
5.74
0
Simpsons Rule
A = D/3[ O1+ON + 4 (O2+O4+O6….) +2(O3+O5+O7…)]
A1 = 10/3 [ (0+4.84) + 4(2.68+3.70+3.62) +2(3.64+4.60)]
= 204.4M2
A2 = 10/2[4.84+5.74] = 52.9M2
TOTAL AREA A= A1+A2
= 204.4+52.9
= 257.3M2](https://image.slidesharecdn.com/areacalculations-220825071247-4ab6b2f8/75/area-calculations-pptx-4-2048.jpg)
area calculations.pptx
- 1. 0, 2.68 3.643.70 4.60 3.62 4.84 5.74 10 10 10 10 10 10 10 0 2.68 3.64 3.70 4.60 3.62 4.84 5.74 Simpson rule Area1 = d/3(o1+07)+4(o2+o4+o6)+2(03+o5) 10/3 [ 0+4.84+4(2.68+3.70+3.62)+2(3.64+4.60)] = 204.4m2 Area2 = 10/2(4.84+5.74) = 52.9m2 Total area = 204.4+52.9 = 257.3m2 Trapezoidal rule Area = d[(o1+on)/2 +o2+o3+o4……on-1] = 10 [ (0+5.74)/2 + 2.68+3.64+3.70+4.60+3.62+4.84] = 259.5m2
- 2. D = 5 Ordinates O12.72 02 3.46 O3 5.23 O4 6.80 O5 4.86 O6 3.35 07 3.00 08 2.50 09 1.60 o1 o9 Trapezoidal rule A = 5[(2.72+1.60)/2+3.46+5.23+6.80+4.86+3.35+3+2.50] = 156.8m2 Simpsons rule A = 5/3[ (2.72+1.60) +4(3.46+6.80+3.35+2.50)+2(5.23+4.86+3) = 158.23m2
- 3. Chainage 0 820 35 47 60 Offsets 14.5 24.5 30.8 27.4 28.4 18.4
- 4. 2.10 3.15 4.503.60 4.58 7.85 6.45 4.65 3.14 Trapezoidal Rule A = d[ (o1+on)/2 + o2+o3+o4……on-1] = 10[ (0+5.74)/2 + 2.68+3.64+3.7+4.6+3.62+4.84] = 259.5m2 0 2.68 3.64 3.70 4.60 3.62 4.84 5.74 D= 10m 2.68 3.64 3.70 4.60 3.62 4.84 5.74 0 Simpsons Rule A = D/3[ O1+ON + 4 (O2+O4+O6….) +2(O3+O5+O7…)] A1 = 10/3 [ (0+4.84) + 4(2.68+3.70+3.62) +2(3.64+4.60)] = 204.4M2 A2 = 10/2[4.84+5.74] = 52.9M2 TOTAL AREA A= A1+A2 = 204.4+52.9 = 257.3M2