Area of a triangle 
and parallelogram 
STANDARD : 7TH
• The area of any shape is a measure of the 2 dimensional 
space that it covers. 
• Area is measured in squares – e.g. square cm, square meters 
and square km.
What is the area 
L=length H=height 
of this parallelogram? 
W=width
PARALLELOGRAM 
What is the area 
L=length H=height 
of this parallelogram? 
W=width 
CUT HERE
What is the area 
of this parallelogram? 
Move and paste Here 
B= base 
H=height 
 This Is ( like) a rectangle obtained from Parallelogram 
Area of Rectangle = Area of parallelogram
Area of Rectangle= Base x Height 
(perpendicular height H) 
B= base 
H=height 
L=length 
B = base 
H=height
Find the area of parallelogram whose base is 30 cm and 
height is 20cm 
Suppose ABCD is a parallelogram 
Given : l ( BC ) = 30 cm , l ( AE ) = 20 cm 
To find out : A ( )ABCD 
Area of Parallelogram= Base x 
Height 
A 
B 
D 
20 cm 
E C 
A ( )ABCD = l ( BC ) × l ( AE ) 30 cm 
= 30cm× 20cm 
= 600 sq cm 
Solution : 
The area of parallelogram is 600 sq cm
If the area of parallelogram is 250 sq cm and its height is 
25 cm , what is the length of its base. 
Suppose DEFG is a parallelogram 
Given : l ( DH ) = 25 cm , A ( DEFG ) = 250 sq cm 
To find out : l ( EF ) =? 
SOLUTION : 
Area of Parallelogram= Base x Height 
A ( DEFG ) = l ( EF ) × l ( DH) 
250 cmxcm = l ( EF) x 25 cm 
250 Xcm Xcm = l ( EF) 
25 xcm 
10 cm = l ( EF) 
The length of its base is 10 cm 
D 
E F 
G 
H
 EVALUATIVE QUESTIONS
Evaluation: 
 The area of parallelogram ABCD is 300 sqcm . The length of its base 
is 15 cm what will be the height of parallelogram. 
 If the length of base of parallelogram is 15 cm and its height is 30 cm. 
find o the area of parallelogram. 
 The area of parallelogram ABCD is 450 sqcm . The length of its 
height is 9 cm what will be the base of parallelogram.
L=length H=height 
What is the area 
of this triangle? 
W=width 
COPY THIS
PASTE HERE 
H=height 
W=width 
L=length 
cho
L=length H=height 
W=width 
FLIP HORIZONTALLY!
The area of the 
L=length H=height 
triangle is ½ the 
B = Base 
Area of triangle= ½ (Base x Height) 
INVERT HERE 
area of this 
parallelogram
8cm 
10cm 
6cm 
7cm 
Area of triangle =½ base X height 
= ½ x 10 cm x 8cm 
= ½ x 80 sq cm 
=40 sq cm 
Area of triangle =½ base X height 
= ½ x 6cm x 7cm 
= ½x42sqcm 
=21 sq cm 
EXAMPLES
If the area of triangle is 90 sq m and its base 
is 20 m , what is the length of its height. 
J 
k L M 
Suppose JKM is a triangle 
Given : A( JKM ) = 90 sq m , l ( KM ) = 20 m 
To find out : l ( JL ) 
Solution : 
Area of triangle =½ X base X height 
90sqm = ½ X l ( KM )X l 
The length of height of triangle is 9m 
(JL) 
90sqm = ½ X 20 m X l (JL) 
90sqm = 10m X l (JL) 
9m = l (JL)
 The area of triangle GEF is 100 sqcm . The length of its 
base is 25 cm. what will be the height of triangle. 
 If the length of base of triangle is 12 cm and its height is 
27 cm. find out the area of triangle. 
 The area of triangle RPS is 120 sqcm . The length of its 
height is 5 cm what will be the base of triangle.
Area of a triangle and parallelogram

Area of a triangle and parallelogram

  • 1.
    Area of atriangle and parallelogram STANDARD : 7TH
  • 2.
    • The areaof any shape is a measure of the 2 dimensional space that it covers. • Area is measured in squares – e.g. square cm, square meters and square km.
  • 4.
    What is thearea L=length H=height of this parallelogram? W=width
  • 5.
    PARALLELOGRAM What isthe area L=length H=height of this parallelogram? W=width CUT HERE
  • 6.
    What is thearea of this parallelogram? Move and paste Here B= base H=height  This Is ( like) a rectangle obtained from Parallelogram Area of Rectangle = Area of parallelogram
  • 7.
    Area of Rectangle=Base x Height (perpendicular height H) B= base H=height L=length B = base H=height
  • 8.
    Find the areaof parallelogram whose base is 30 cm and height is 20cm Suppose ABCD is a parallelogram Given : l ( BC ) = 30 cm , l ( AE ) = 20 cm To find out : A ( )ABCD Area of Parallelogram= Base x Height A B D 20 cm E C A ( )ABCD = l ( BC ) × l ( AE ) 30 cm = 30cm× 20cm = 600 sq cm Solution : The area of parallelogram is 600 sq cm
  • 9.
    If the areaof parallelogram is 250 sq cm and its height is 25 cm , what is the length of its base. Suppose DEFG is a parallelogram Given : l ( DH ) = 25 cm , A ( DEFG ) = 250 sq cm To find out : l ( EF ) =? SOLUTION : Area of Parallelogram= Base x Height A ( DEFG ) = l ( EF ) × l ( DH) 250 cmxcm = l ( EF) x 25 cm 250 Xcm Xcm = l ( EF) 25 xcm 10 cm = l ( EF) The length of its base is 10 cm D E F G H
  • 10.
  • 11.
    Evaluation:  Thearea of parallelogram ABCD is 300 sqcm . The length of its base is 15 cm what will be the height of parallelogram.  If the length of base of parallelogram is 15 cm and its height is 30 cm. find o the area of parallelogram.  The area of parallelogram ABCD is 450 sqcm . The length of its height is 9 cm what will be the base of parallelogram.
  • 13.
    L=length H=height Whatis the area of this triangle? W=width COPY THIS
  • 14.
    PASTE HERE H=height W=width L=length cho
  • 15.
    L=length H=height W=width FLIP HORIZONTALLY!
  • 16.
    The area ofthe L=length H=height triangle is ½ the B = Base Area of triangle= ½ (Base x Height) INVERT HERE area of this parallelogram
  • 17.
    8cm 10cm 6cm 7cm Area of triangle =½ base X height = ½ x 10 cm x 8cm = ½ x 80 sq cm =40 sq cm Area of triangle =½ base X height = ½ x 6cm x 7cm = ½x42sqcm =21 sq cm EXAMPLES
  • 18.
    If the areaof triangle is 90 sq m and its base is 20 m , what is the length of its height. J k L M Suppose JKM is a triangle Given : A( JKM ) = 90 sq m , l ( KM ) = 20 m To find out : l ( JL ) Solution : Area of triangle =½ X base X height 90sqm = ½ X l ( KM )X l The length of height of triangle is 9m (JL) 90sqm = ½ X 20 m X l (JL) 90sqm = 10m X l (JL) 9m = l (JL)
  • 19.
     The areaof triangle GEF is 100 sqcm . The length of its base is 25 cm. what will be the height of triangle.  If the length of base of triangle is 12 cm and its height is 27 cm. find out the area of triangle.  The area of triangle RPS is 120 sqcm . The length of its height is 5 cm what will be the base of triangle.