TOPIC: ASSIGNMENT MODEL
OPERATION RESEARCH
ASSIGNMENT MODEL
ASSIGNMENT MODEL
• Assigning of jobs to factors (men or machine) to
get most optimum output or get least cost.
• Hungarian method is the mostly used method of
solving assignment problems.
• Types of Assignment problems:
(i) Balanced
(ii) Unbalanced
OBJECTIVES
(i) No workers is more than one job.
(ii) No job is allotted to more than one worker.
(iii)Total time taken to complete a job is
minimum.
(iv)The work done is cost effective.
BALANCED ASSIGNMENT
• An assignment is called balanced assignment problem if
the number of persons (factors) is same as the number
of jobs.
J1 J2 J3 _ _ _ _ _ _ _ _ _ _ _ _ Jn
P1 T11 T12 T13 _ _ _ _ _ _ _ _ _ _ _ _ T1n
P2 T21 T22 T23 _ _ _ _ _ _ _ _ _ _ _ _ T2n
P3 T31 T32 T33 _ _ _ _ _ _ _ _ _ _ _ _ T3n
I I I I _ _ _ _ _ _ _ _ _ _ _ _ I
I I I I _ _ _ _ _ _ _ _ _ _ _ _ I
Pn Tn1 Tn2 Tn3 _ _ _ _ _ _ _ _ _ _ _ _ Tnn
EXAMPLE OF BALANCED PROBLEM
1 2 3 4
A 1 8 4 1
B 5 7 6 5
C 3 5 4 12
D 3 1 6 3
PROFITS (IN 1000’s)
PLANTS
Solve the following assignment problem to get
maximum profit:
METHOD
STEP 1
• Subtract all the element of
each row from the largest
elements of respective
rows.
STEP 2
• Subtract the least element of
each column from other
elements of respective
column and allot jobs.
1 2 3 4
A 7 0 4 7
B 2 0 1 2
C 9 7 8 0
D 3 5 0 3
PROFIT
S
PLANTS
PROFITS
PLANTS
1 2 3 4
A 5 0 4 7
B 0 0 1 2
C 7 7 8 0
D 1 5 0 3
0
METHOD
• Hence the optimum solution is:
(i) A2
(ii) B1
(iii) C4
(iv) D3
Hence the total profit will be
8000+ 5000+ 12000 +6000 = 31000
8000
8000
12000
6000
UNBALANCED ASSIGNMENT
• An assignment is called unbalanced assignment problem
if the number of persons (factors) is not same as the
number of jobs.
J1 J2 J3 _ _ _ _ _ _ _ _ _ _ _ _ Jn-1
P1 T11 T12 T13 _ _ _ _ _ _ _ _ _ _ _ _ T1(n-1)
P2 T21 T22 T23 _ _ _ _ _ _ _ _ _ _ _ _ T2(n-1)
P3 T31 T32 T33 _ _ _ _ _ _ _ _ _ _ _ _ T3(n-1)
I I I I _ _ _ _ _ _ _ _ _ _ _ _ I
I I I I _ _ _ _ _ _ _ _ _ _ _ _ I
Pn Tn1 Tn2 Tn3 _ _ _ _ _ _ _ _ _ _ _ _ Tn(n-1)
EXAMPLE OF UNBALANCED PROBLEM
Solve the following assignment problem to get it
completed in least time:
A B C D E
1 62 78 50 101 82
2 71 84 61 73 59
3 87 92 111 71 81
4 48 64 87 77 80
JOBS
MACHINES
5 0 0 0 0 0
METHOD
Subtract all the element of each row from
the largest elements of respective rows.
•STEP 1
A B C D E
1 39 23 51 0 19
2 13 0 23 11 25
3 24 19 0 40 30
4 39 23 0 10 7
5 0 0 0 0 0
JOBS
MACHINES
METHOD
Subtract the least element of each column
from other elements of respective column
and allot jobs.
•STEP 2
V A B C D E
1 39 23 51 0 19
2 13 0 23 11 25
3 24 19 0 40 30
4 39 23 0 10 7
5 0 0 0 0 0
JOBS
MACHINES
0
0 0 0 0
METHOD
Cancel all zeros by drawing lines less than
the number of rows or columns.
•STEP 3
A B C D E
1 39 23 51 0 19
2 13 0 23 11 25
3 24 19 0 40 30
4 39 23 0 10 7
5 0 0 0 0 0
JOBS
MACHINES
METHOD
Choose the least uncovered element and
add it to all intersection points and subtract
it from all uncovered elements.
•STEP 4
A B C D E
1 32 23 51 0 12
2 6 0 23 11 18
3 17 19 0 40 23
4 32 23 0 10 0
5 0 7 7 7 0
JOBS
MACHINES
0
0
METHOD
• Hence the optimum solution is:
(i) A5 0
(ii) B2 84
(iii) C3 111
(iv) D1 101
(v) E4 80
Hence the total profit will be
0+ 84+ 111 +101+ 80 = 376
THANK YOU

Assignment model

  • 1.
  • 2.
  • 3.
    ASSIGNMENT MODEL • Assigningof jobs to factors (men or machine) to get most optimum output or get least cost. • Hungarian method is the mostly used method of solving assignment problems. • Types of Assignment problems: (i) Balanced (ii) Unbalanced
  • 4.
    OBJECTIVES (i) No workersis more than one job. (ii) No job is allotted to more than one worker. (iii)Total time taken to complete a job is minimum. (iv)The work done is cost effective.
  • 5.
    BALANCED ASSIGNMENT • Anassignment is called balanced assignment problem if the number of persons (factors) is same as the number of jobs. J1 J2 J3 _ _ _ _ _ _ _ _ _ _ _ _ Jn P1 T11 T12 T13 _ _ _ _ _ _ _ _ _ _ _ _ T1n P2 T21 T22 T23 _ _ _ _ _ _ _ _ _ _ _ _ T2n P3 T31 T32 T33 _ _ _ _ _ _ _ _ _ _ _ _ T3n I I I I _ _ _ _ _ _ _ _ _ _ _ _ I I I I I _ _ _ _ _ _ _ _ _ _ _ _ I Pn Tn1 Tn2 Tn3 _ _ _ _ _ _ _ _ _ _ _ _ Tnn
  • 6.
    EXAMPLE OF BALANCEDPROBLEM 1 2 3 4 A 1 8 4 1 B 5 7 6 5 C 3 5 4 12 D 3 1 6 3 PROFITS (IN 1000’s) PLANTS Solve the following assignment problem to get maximum profit:
  • 7.
    METHOD STEP 1 • Subtractall the element of each row from the largest elements of respective rows. STEP 2 • Subtract the least element of each column from other elements of respective column and allot jobs. 1 2 3 4 A 7 0 4 7 B 2 0 1 2 C 9 7 8 0 D 3 5 0 3 PROFIT S PLANTS PROFITS PLANTS 1 2 3 4 A 5 0 4 7 B 0 0 1 2 C 7 7 8 0 D 1 5 0 3 0
  • 8.
    METHOD • Hence theoptimum solution is: (i) A2 (ii) B1 (iii) C4 (iv) D3 Hence the total profit will be 8000+ 5000+ 12000 +6000 = 31000 8000 8000 12000 6000
  • 9.
    UNBALANCED ASSIGNMENT • Anassignment is called unbalanced assignment problem if the number of persons (factors) is not same as the number of jobs. J1 J2 J3 _ _ _ _ _ _ _ _ _ _ _ _ Jn-1 P1 T11 T12 T13 _ _ _ _ _ _ _ _ _ _ _ _ T1(n-1) P2 T21 T22 T23 _ _ _ _ _ _ _ _ _ _ _ _ T2(n-1) P3 T31 T32 T33 _ _ _ _ _ _ _ _ _ _ _ _ T3(n-1) I I I I _ _ _ _ _ _ _ _ _ _ _ _ I I I I I _ _ _ _ _ _ _ _ _ _ _ _ I Pn Tn1 Tn2 Tn3 _ _ _ _ _ _ _ _ _ _ _ _ Tn(n-1)
  • 10.
    EXAMPLE OF UNBALANCEDPROBLEM Solve the following assignment problem to get it completed in least time: A B C D E 1 62 78 50 101 82 2 71 84 61 73 59 3 87 92 111 71 81 4 48 64 87 77 80 JOBS MACHINES 5 0 0 0 0 0
  • 11.
    METHOD Subtract all theelement of each row from the largest elements of respective rows. •STEP 1 A B C D E 1 39 23 51 0 19 2 13 0 23 11 25 3 24 19 0 40 30 4 39 23 0 10 7 5 0 0 0 0 0 JOBS MACHINES
  • 12.
    METHOD Subtract the leastelement of each column from other elements of respective column and allot jobs. •STEP 2 V A B C D E 1 39 23 51 0 19 2 13 0 23 11 25 3 24 19 0 40 30 4 39 23 0 10 7 5 0 0 0 0 0 JOBS MACHINES 0 0 0 0 0
  • 13.
    METHOD Cancel all zerosby drawing lines less than the number of rows or columns. •STEP 3 A B C D E 1 39 23 51 0 19 2 13 0 23 11 25 3 24 19 0 40 30 4 39 23 0 10 7 5 0 0 0 0 0 JOBS MACHINES
  • 14.
    METHOD Choose the leastuncovered element and add it to all intersection points and subtract it from all uncovered elements. •STEP 4 A B C D E 1 32 23 51 0 12 2 6 0 23 11 18 3 17 19 0 40 23 4 32 23 0 10 0 5 0 7 7 7 0 JOBS MACHINES 0 0
  • 15.
    METHOD • Hence theoptimum solution is: (i) A5 0 (ii) B2 84 (iii) C3 111 (iv) D1 101 (v) E4 80 Hence the total profit will be 0+ 84+ 111 +101+ 80 = 376
  • 16.