Basics of thermodynamics

Basics of ThermodynamicsBasics of Thermodynamics
Four Laws that Drive the Universe
Peter Atkins*
Oxford University Press, Oxford, 2007
Reading
Some of the material covered here is also covered in the chapter/topic on:
Equilibrium
*It is impossible for me to write better than Atkins- his lucid (& humorous) writing style is truly impressive- paraphrasing may lead to loss of
the beauty of his statements- hence, some parts are quoted directly from his works.
MATERIALS SCIENCEMATERIALS SCIENCE
&&
ENGINEERINGENGINEERING
Anandh Subramaniam & Kantesh Balani
Materials Science and Engineering (MSE)
Indian Institute of Technology, Kanpur- 208016
Email: anandh@iitk.ac.in, URL: home.iitk.ac.in/~anandh
AN INTRODUCTORY E-BOOKAN INTRODUCTORY E-BOOK
Part of
http://home.iitk.ac.in/~anandh/E-book.htm
A Learner’s GuideA Learner’s GuideA Learner’s GuideA Learner’s Guide
Physical Chemistry
Ira N Levine
Tata McGraw Hill Education Pvt. Ltd., New York (2002).

 Thermodynamics deals with stability of systems. It tells us ‘what should
happen?’. ‘Will it actually happen(?)’ is not the domain of thermodynamics and
falls under the realm of kinetics.
 At –5°C at 1 atm pressure, ice is more stable then water. Suppose we cool water
to –5°C. “Will this water freeze?” (& “how long will it take for it to freeze?”) is
(are) not questions addressed by thermodynamics.
 Systems can remain in metastable state for a ‘long-time’.
 Window pane glass is metastable– but it may take geological time scales for it
to crystallize!
 At room temperature and atmospheric pressure, graphite is more stable then
diamond– but we may not lose the glitter of diamond practically forever!
Thermodynamics versus Kinetics
* The term metastable is defined in the chapter on equilibrium.

 One branch of knowledge that all engineers and scientists must have a grasp of
(to some extent or the other!) is thermodynamics.
 In some sense thermodynamics is perhaps the ‘most abstract subject’ and a
student can often find it very confusing if not ‘motivated’ strongly enough.
 Thermodynamics can be considered as a ‘system level’ science- i.e. it deals with
descriptions of the whole system and not with interactions (say) at the level of
individual particles.
• I.e. it deals with quantities (like T,P) averaged over a large collection of entities
(like molecules, atoms)*.
• This implies that questions like: “What is the temperature or entropy of an
atom?”; do not make sense in the context of thermodynamics (at lease in the usual way!).
 TD puts before us some fundamental laws which are universal** in nature (and
hence applicable to fields across disciplines).
Thermodynamics (TD): perhaps the most basic science
* Thermodynamics deals with spatio-temporally averaged quantities.
** They apply to the universe a whole as well! (Though the proof is lacking!).

 To understand the laws of thermodynamics and how they work, first we need to get the
terminology right. Some of the terms may look familiar (as they are used in everyday
language as well)- but their meanings are more ‘technical’ and ‘precise’, when used in TD
and hence we should not use them ‘casually’.
 System is region where we focus our attention (Au block in figure).
 Surrounding is the rest of the universe (the water bath at constant ‘temperature’).
 Universe = System + Surrounding (the part that is within the dotted line box in the figure below)
 More practically, we can consider the ‘Surrounding’ as the immediate neighbourhood of the
system (the part of the universe at large, with which the system ‘effectively’ interacts).
In this scheme of things we can visualize: a system, the surrounding and the universe at
large.
 Things that matter for the surrounding: (i) T (ii) P (iii) ability to: do work, transfer heat,
transfer matter, etc. Parameters for the system: (i) Internal energy, (ii) Enthapy, (iii) T, (iv)
P, (v) mass, etc.
The language of TD
In TD we usually do not worry
about the universe at large!

 To a thermodynamic system two ‘things’ may be added/removed:
 energy (heat, work)  matter.
 An open system is one to which you can add/remove matter (e.g. a open beaker to which
we can add water). When you add matter- you also end up adding heat (which is
contained in that matter).
 A system to which you cannot add matter is called closed.
Though you cannot add/remove matter to a closed system, you can still add/remove heat
(you can cool a closed water bottle in fridge).
 A system to which neither matter nor heat can be added/removed is called isolated.
A closed vacuum ‘thermos’ flask can be considered as isolated.
Open, closed and isolated systems
Type of boundary Interactions
Open All interactions possible (Mass, Work, Heat)
Closed Matter cannot enter or leave
Semi-permeable Only certain species can enter or leave
Insulated Heat cannot enter or leave
Rigid Mechanical work cannot be done*
Isolated No interactions are possible**
* By or on the system
** Mass, Heat or Work
Mass
Heat
Work
Interactions possible

 Matter is easy to understand and includes atoms, ions, electrons, etc.
 Energy may be transferred (‘added’) to the system as heat, electromagnetic radiation etc.
 In TD the two modes of transfer of energy to the system considered are Heat and Work.
 Heat and work are modes of transfer of energy and not ‘energy’ itself.
 Once inside the system, the part which came via work and the part which came via
heat, cannot be distinguished*. More sooner on this!
 Before the start of the process and after the process is completed, the terms heat and
work are not relevant.
 From the above it is clear that, bodies contain internal energy and not heat (nor work!).
 Matter when added to a system brings along with it some energy. The ‘energy density’
(energy per unit mass or energy per unit volume) in the incoming matter may be higher or lower than the
matter already present in the system.
* The analogy usually given is that of depositing a cheque versus a draft in a bank. Once credited to an account, cheque and draft have no
meaning. (Also reiterated later).

 Here is a brief listing of a few kinds of processes, which we will encounter in TD:
 Isothermal process → the process takes place at constant temperature
(e.g. freezing of water to ice at –10°C)
 Isobaric → constant pressure
(e.g. heating of water in open air→ under atmospheric pressure)
 Isochoric → constant volume
(e.g. heating of gas in a sealed metal container)
 Reversible process → the system is close to equilibrium at all times (and infinitesimal
alteration of the conditions can restore the universe (system + surrounding) to the original
state.
 Cyclic process → the final and initial state are the same. However, q and w need not be
zero.
 Adiabatic process → dq is zero during the process (no heat is added/removed to/from the
system)
 A combination of the above are also possible: e.g. ‘reversible adiabatic process’.
Processes in TD We will deal with some of them in detail later on

 Though we all have a feel for temperature (‘like when we are feeling hot’); in the context
of TD temperature is technical term with ‘deep meaning’.
 As we know (from a commons sense perspective) that temperature is a measure of the ‘intensity of
heat’. ‘Heat flows’ (energy is transferred as heat) from a body at higher temperature to one at lower
temperature. (Like pressure is a measure of the intensity of ‘force applied by matter’→
matter (for now a fluid) flows from region of higher pressure to lower pressure).
 That implies (to reiterate the obvious!) if I connect two bodies− (A)-one weighing 100kg at 10°C
and the other (B) weighing 1 kg at 500°C, then the ‘heat will flow’ from the hotter body
to the colder body (i.e. the weight or volume of the body does not matter).
 But, temperature comes in two important ‘technical’ contexts in TD:
1 it is a measure of the average kinetic energy (or velocity) of the constituent entities (say molecules)
2 it is the parameter which determines the distribution of species (say molecules) across
various energy states available.
Temperature
500°C
Heat flow
direction
10°C
A B

 Let us consider various energy levels available for molecules in a system to be promoted to.
 At low temperatures the lower energy levels are expected to be populated more, as compared
to higher energy levels. As we heat the system, more and more molecules will be promoted to
higher energy levels.
 The distribution of molecules across these energy levels is given by:
Temperature as a parameter determining the distribution of species across energy levels

 Celsius (Farenheit, etc.) are relative scales of temperature and zero of these scales do not have
a fundamental significance. Kelvin scale is a absolute scale. Zero Kelvin and temperatures
below that are not obtainable in the classical sense.
 Classically, at 0K a perfect crystalline system has zero entropy (i.e. system attains its minimum
entropy state). However, in some cases there could be some residual entropy due to
degeneracy of states.
 At 0K the kinetic energy of the system is not zero. There exists some zero point energy.
Few points about temperature scales and their properties

 Pressure* is force per unit area (usually exerted by a fluid on a wall**).
 It is the momentum transferred (say on a flat wall by molecules of a gas) per unit area, per unit time. (In
the case of gas molecules it is the average momentum transferred per unit area per unit time on to the flat wall).
 P = momentum transferred/area/time.
 Pressure is related to momentum, while temperature is related to kinetic energy.
Pressure
Wallofacontainer
‘Crude schematic’
of particles
impinging on a
wall.
* ‘Normal’ pressure is also referred to as hydrostatic pressure.
** Other agents causing pressure could be radiation, macroscopic objects impinging on a wall, etc.

 Work (W) in mechanics is displacement (d) against a resisting force (F). W = F × d
 Work has units of energy (Joule, J).
 Work can be expansion work (P∆V), electrical work, magnetic work etc. (many sets of
stimuli and their responses).
 Heat as used in TD is a tricky term (yes, it is a very technical term as used in TD).
 The transfer of energy as a result of a temperature difference is called heat.
 “In TD heat is NOT an entity or even a form of energy; heat is a mode of transfer of
energy” [1].
 “Heat is the transfer of energy by virtue of a temperature difference” [1].
 “Heat is the name of a process, not the name of an entity” [1].
 “Bodies contain internal energy (U) and not heat” [2].
 The ‘flow’ of energy down a temperature gradient can be treated mathematically by
considering heat as a mass-less fluid [1] → this does not make heat a fluid!
Heat and Work
[1] Four Laws that Drive the Universe, Peter Atkins, Oxford University Press, Oxford, 2007. [2] Physical Chemistry, Ira N Levine, Tata McGraw Hill Education Pvt. Ltd., New York (2002).
To give an example (inspired by [1]):
assume that you start a rumour that there is ‘lot of’ gold under the class room floor. This rumour ‘may’ spread when persons talk to each other.
The ‘spread of rumor’ with time may be treated mathematically by equations, which have a form similar to the diffusion equations (or heat
transfer equations). This does not make ‘rumour’ a fluid!
Expansion work

 Work is coordinated flow of matter.
 Lowering of a weight can do work
 Motion of piston can do work
 Flow of electrons in conductor can do work.
 Heat involves random motion of matter (or the constituent entities of matter).
 Like gas molecules in a gas cylinder
 Water molecules in a cup of water
 Atoms vibrating in a block of Cu.
 Energy may enter the system as heat or work.
 Once inside the system:
• it does not matter how the energy entered the system* (i.e. work and heat are terms
associated with the surrounding and once inside the system there is no ‘memory’ of how
the input was received and
• the energy is stored as potential energy (PE) and kinetic energy (KE).
 This energy can be withdrawn as work or heat from the system.
* As Aktins put it: “money may enter a back as cheque or cash− but once inside the bank there is no difference”.

 A reversible process is one where an infinitesimal change in the conditions of the
surroundings leads to a ‘reversal’ of the process. (The system is very close to equilibrium
and infinitesimal changes can restore the system and surroundings to the original state).
 If a block of material (at T) is in contact with surrounding at (T−δT), then ‘heat will flow’
into the surrounding. Now if the temperature of the surrounding is increased to (T+δT),
then the direction of heat flow will be reversed.
 If a block of material (at 40°C) is contact with surrounding at 80°C then the ‘heat transfer’
with takes place is not reversible.
 Though the above example uses temperature differences to illustrate the point, the situation
with other stimuli like pressure (differences) is also identical.
 Consider a piston with gas in it a pressure ‘P’. If the external pressure is (P+δP), then the
gas (in the piston) will be compressed (slightly). The reverse process will occur if the
external (surrounding pressure is slightly lower).
 Maximum work will be done if the compression (or expansion) is carried out in a reversible
manner.
Reversible process
T
Heat flow
direction
T+δT
T
Heat flow
direction
T−δT
Reversible process
40°C
Heat flow
direction
80°C
NOT a Reversible process
‘Reversible’ is a technical term (like many others) in the context of TD.

 Let us keep one example in mind as to how we can (sometimes) construct a ‘reversible’
equivalent to a ‘irreversible’ processes.
 Let us consider the example of the freezing of ‘undercooled water’* at –5°C (at 1 atm
pressure). This freezing of undercooled water is irreversible (P1 below).
 We can visualize this process as taking place in three reversible steps  hence making the
entire process reversible (P2 below).
How to visualize a ‘reversible’ equivalent to a ‘irreversible’ processes?
* ‘Undercooled’ implies that the water is held in the liquid state below the bulk freezing point! How is this possible?→ read chapter on phase
transformations
Water at –5°C Ice at –5°C
Irreversible
Water at –5°C
Water at –0°C
Reversible
Ice at –0°C
Ice at –5°C
Heat CoolP2
P1

 ‘Ultimately’, all forms of energy will be converted to heat!!
 One nice example given by Atkins: consider a current through a heating wire of a resistor.
There is a net flow of electrons down the wire (in the direction of the potential gradient)
→ i.e. work is being done.
Now the electron collisions with various scattering centres leading to heating of the wire
→ i.e. work has been converted into heat.
P
 In a closed system (piston in the example figure below), if infinitesimal pressure increase
causes the volume to decrease by ∆V, then the work done on the system is:
 The system is close to equilibrium during the whole process
thus making the process reversible.
 As ∆V is negative, while the work done is positive (work done on the system is positive,
work done by the system is negative).
If the piston moves outward under influence of P (i.e. ‘P’ and ∆V are in opposite directions,
then work done is negative.
Reversible P-V work on a closed system
reversibledw PdV= −
1
2

 A property which depends only on the current state of the system (as defined by T, P, V
etc.) is called a state function. This does not depend on the path used to reach a particular
state.
 Analogy: one is climbing a hill- the potential energy of the person is measured by the
height of his CG from ‘say’ the ground level. If the person is at a height of ‘h’ (at point P),
then his potential energy will be mgh, irrespective of the path used by the person to reach
the height (paths C1 & C2 will give the same increase in potential energy of mgh- in figure
below).
 In TD this state function is the internal energy (U or E). (Every state of the system can be ascribed to a unique U).
 Hence, the work needed to move a system from a state of lower internal energy (=UL) to a
state of higher internal energy (UH) is (UH) − (UL). W = (UH) − (UL)
 The internal energy of an isolated system (which exchages neither heat nor mass) is
constant → this is one formulation of the first law of TD.
 A process for which the final and initial states are same is called a cyclic process. For a
cyclic process change in a state function is zero.
E.g. ∆U(cyclic process) = 0.
State functions in TD

 A spontaneous process is one which occurs ‘naturally’, ‘down-hill’ in energy*. I.e. the
process does not require input of work in any form to take place.
• Melting of ice at 50°C is a spontaneous process.
 A driven process is one which wherein an external agent takes the system uphill in energy
(usually by doing work on the system).
• Freezing of water at 50°C is a driven process (you need a refrigerator, wherein electric
current does work on the system).
 Later on we will note that the entropy of the universe will increase during a spontaneous
change. (I.e. entropy can be used as a single parameter for characterizing spontaneity).
Spontaneous and Driven processes
Spontaneous process
(Click to see)
* The kind of ‘energy’ we are talking about depends on the conditions. As in the topic on Equilibrium, at constant temperature and pressure the
relevant TD energy is Gibbs free energy.

 Heat capacity is the amount of heat (measured in Joules or Calories) needed to raise an
unit amount of substance (measured in grams or moles) by an unit in temperature
(measured in °C or K). As mentioned before bodies (systems) contain internal energy and not heat.
 This ‘heating’ (addition of energy) can be carried out at constant volume or constant
pressure. At constant pressure, some of the heat supplied goes into doing work of
expansion and less is available with the system (to raise it temperature).
 Heat capacity at constant Volume (CV):
It is the slope of the plot of internal energy with temperature.
 Heat capacity at constant Pressure (CP):
It is the slope of the plot of enthalpy with temperature.
 Units: Joules/Kelvin/mole, J/K/mole, J/°C/mole, J/°C/g.
 Heat capacity is an extensive property (depends on ‘amount of matter’)
 If a substance has higher heat capacity, then more heat has to be added to raise its
temperature. Water with a high heat capacity (of CP = 4186 J/K/mole =1 Cal/°C/Kg) heats
up slowly as compared to air (with a heat capacity, CP = 29.07J/K/mole) ⇒ this implies that
oceans will heat up slowly as compared to the atomosphere.
 As T→0K, the heat capacity tends to zero. I.e near 0 Kelvin very little heat is required to
raise the temperature of a sample. (This automatically implies that very little heat has to
added to raise the temperature of a material close to 0K.
This is of course bad news for cooling to very low temperatures− small leakages of heat will lead to drastic increase in temperature).
Heat Capacity
V
V
E
C
T
∂ 
=  ÷
∂ 
P
P
H
C
T
∂ 
=  ÷
∂ 

 The internal energy of an isolated system is constant.
 A closed system may exchange energy as heat or work. Let us consider a close system at
rest without external fields.
 There exists a state function U such that for any process in a closed system:
∆U = q + w [1]
 q → heat flow in to the system
 w → work done on the system (work done by the system is negative of above- this is just ‘one’ sign convention)
q & w are not state functions → i.e. they depend on the path of a process.
 U is the internal energy. Being a state function for a process ∆U depends only of the final
and initial state of the system. ∆U = Ufinal – Uinitial. In contrast to U, q & w are NOT state
functions (i.e. depend on the path followed).
 For an infinitesimal process eq. [1] can be written as: dU = dq + dw
 The change in U of the surrounding will be opposite in sign, such that:
∆Usystem + ∆Usurrounding = 0
 Actually, it should be ∆E above and not ∆U {however, in many cases K and V are zero
(e.g. a system at rest considered above) and the above is valid- as discussed elsewhere}.
 It is to be noted that in ‘w’ work done by one part of the system on another part is not included.
The Laws of Thermodynamics The First Law

 It is impossible to build a cyclic machine* that converts heat into work with 100%
efficiency → Kelvin’s statement of the second law.
 Another way of viewing the same:
it is impossible to construct a cyclic machine** that completely (with 100% efficiency)
converts heat, which is energy of random molecular motion, to mechanical work, which is
ordered motion.
 The unavailable work is due to the role of Entropy in the process.
The Second Law
Heat reservoir Cyclic engine
Heat q
Work (w)100%
Not possible
Heat reservoir Cyclic engine
Heat q
Work (w)
Cold Reservoir
Heat q’

×
Kelvin’s
statement of the
second law
The second law comes in many equivalent forms
* For now we are ‘building’ ‘conceptual machines’ !
** These ‘engines’ which use heat and try to produce work are called heat engines.
Called the
sink
Possible
Called the
source

 Heat does not ‘flow*’ from a colder body to a hotter body, without an concomitant change
outside of the two bodies→ Clausius’s statement of the second law.(a)
 This automatically implies that the spontaneous direction of the ‘flow of heat*’ is from a
hotter body to a colder body.(b)
 The Kelvin’s and Clausius’s statements of the second law are equivalent. I.e. if we violate
Kelvin’s statement, then we will automatically violate the Clausius’s statement of the
second law (and vice-versa).
Another statement of the second law → the Clausius statement
* Used here in the ‘common usage sense’.
(b) is obvious, but not (a) → though they represent the same fact.

 The entropy* of a closed system will increase during any spontaneous change.
If we consider the Universe to be a closed system (without proof!!)**, then
 The entropy of the universe will increase during any spontaneous change (process).
A combined (Kelvin + Clausius) statement of the II Law
* Soon we will get down to this mysterious quantity.
** For all we know the Universe could be ‘leaky’ with wormholes to other parallel Universes!
You may want to jump to chapter on
equilibrium to know about Entropy first
You may want to jump to chapter on
equilibrium to know about Entropy first

 The efficiency of a heat engine is the amount of work output divided by the amount of heat
input.
 This efficiency depends only on the ratio of the temperature of the sink to the temperature
of the source. The maximum efficiency achievable is given by the formula below.
 This is surprising as:
• there is no mention of the medium of the system (or its properties),
• the formula has only temperatures and
• the temperature of the sink seems to play a major role (as the presence of the sink is
usually not intentional or obvious→ in a steam engine sink is the air around the engine and
source is the hot steam).
Important message Sink (characterized by its temperature) is as important as the source.
 To increase the maximum possible efficiency of a heat engine, either the temperature of the
source has to be increased on the temperature of the sink has to be decreased.
output
heat engine
input
w
q
η = max sink
source
1heat engine
T
T
η
 
= − ÷
 
The efficiency of a heat engine

 Heat cannot spontaneously flow from a cold (low temperature) body to a hot body.
 To make heat flow from a cold body to a hot body, there must be accompanying change
elsewhere (work has to be done to achieve this).
Clausius statement of the second law

Heat reservoir
Heat q
Work (w)
Cold Reservoir
Heat q’
Sin
k
Sourc
e
Q & A What is the difference between ‘heat engine’ and ‘work engine’?
 Actually both the engines we are going to describe here are usually known as heat engines.
 We are differentiating two types of engines to see which one produces work and which one
actually transfers heat.
 In the heat engine as the temperature of the cold body tends to zero Kelvin, more and more
work has to be done to transfer the heat from the cold body to the hot body.
Cyclic engine
‘Work engine’
Hot body
Heat q
Work (w)
Cold Body
Heat q’
Cyclic engine
‘heat engine’
The main objective here
is to produce work
The main objective here is
to transfer heat from a
cold body to a hot body
Like a steam engine Like a refrigerator

 For substances in internal equilibrium, undergoing an isothermal process, the entropy
change goes to zero as T (in K) goes to zero.
The Third Law
0
lim 0
T
S
→
∆ =
 The law is valid for pure substances and mixtures.
 Close to Zero Kelvin, the molecular motions have to be treated using quantum mechanics
→ still it is found that quantum ideal gases obey the third law.
Phenomenological description of the third law.
 There does not exist any finite sequence of cyclical process, which can cool a body to zero
Kelvin (absolute zero).

 To understand the basics often we rely on simple ‘test-bed’ systems.
 In TD one such system is the ideal gas. In an ideal gas the molecules do not interact with
each other (Noble gases come close to this at normal temperatures).
An ideal gas obeys the equation of state:
 As the molecules of a ideal gas do not interact with each other, the internal energy of the
system is expected to be ‘NOT dependent’ on the volume of the system.
I.e.:
 A gas which obeys both the above equations is called a perfect gas.
 Internal energy (a state function) is normally a function of T & V: U = U(T,V).
 For a perfect gas: U = U(T) only.
Ideal and Perfect Gases
PV nRT=
0
T
U
V
∂ 
= ÷
∂ 

 The first law says: “you cannot win”.
 The second law says: “you can at best break even- that too at zero Kelvin”.
 Third law says: “zero Kelvin is unattainable”.
Humorous look at
the three laws
Q & A What is the difference in the ‘status’ of quantities like T, U, S, H, A & G?
 T, U & S are fundamental quantities of thermodynamics.
 H, A & G do not give us new fundamental concepts, but are for better ‘accounting’ in
thermodynamics.

 When we mix two (or for that matter more) elements (A & B), the stable phase will be that
with the lowest G. There are three options here (as we have seen in Chapter 4a):
1 Phase separation → A & B do not want to talk to each other
2 Formation of solid solution → A & B do not care about their environment
3 Compound formation → A & B prefer each other’s environment as compared to their own environment
 In a compound the each one of the components are fixed to their sub-lattices and hence the
configurational entropy of the compound is zero. This is true in the case of a complete
phase separation as well (i.e. the configurational entropy is zero).
 The solid solution is also called a disordered solid solution, in which case each component
is randomly occupies a lattice point without any preference. In practice, there might be
some tendency for ‘ordering’ (i.e. compound formation) or ‘clustering’ (phase separation)
and in that case the ‘random configuration’ assumption will be violated.
What happens when we mix two elements (say Ag and Au→ two crystals)?

 The Gibbs free energy change on mixing (for now we visualize mixing– soon we will see if they actually mix!) is:
∆Gmix = Gmixed state – Gunmixed state = ∆Hmix – T ∆Smix. ∆Hmix = Hmixed state – Hunmixed.
 Hence, if we know two numbers (∆Hmix, ∆Smix) our job is done!
 The game-plan is to find these numbers (especially, ∆Hmix).
 Various models are used for this purpose and that can be quite confusing!
 Each one of these models come with their own baggage of assumptions (& hence approximations).
 The simplest model of mixing is the formation of the ideal solution. In an ideal solution A-
B bonds are energetically no different from the A-A or B-B bonds.
This implies that (∆Hmix)ideal solution = 0.
 If (∆Hmix)ideal solution ≠ 0, which is usually found in practice (i.e. usually the mixing process is
endothermic or exothermic), then we need a more ‘realistic’ computation of ∆Hmix. One of
the popular models is the regular solution model (which is based on the quasi-chemical
approach).
 In real alloys the following factors come into the picture, which can lead to substantial
deviation from the some of the models considered: (i) ordering (if ∆Hmix is very negative),
(ii) clustering (leading to deviation from the random configuration model, (iii) strain in the
lattice due to size difference between the atoms (the quasi-chemical model will
underestimate the change in internal energy on mixing), (iv) substantial size difference
leading to the formation of a interstitial solid solution.

Ideal solution
( ) .mix mixideal solution
G T S∆ = − ∆ ( ln ln )mix A A B BS R X X X X∆ = − +
( ) ( ln ln )mix A A B Bideal solution
G RT X X X X∆ = +
A
Increasing T
B
∆Gmix→
XB →
0

 The regular solution model makes the following assumptions:
(i) the enthalpy of mixing is only due to nearest neighbour atoms,
(ii) volume of A and B (per mole) is the same and there is no volume change due to the
mixing process (interatomic distances and bond energies are independent of the
composition),
(iii) point (ii) above also implies that there is no strain in the lattice.
Regular solution model (quasi-chemical approach)
A B AB+ =
If no. of A-A bonds (per mole) is NAA, the no. of B-B bonds is NBB and the no. of A-B bonds is
NAB and the corresponding bond energies (per bond) are given by EAA, EBB & EAB the internal
energy of the solution is given by (Esolution):
No change in volume
before and after mixing
solution AA AA BB BB AB ABE N E N E N E= + +
The change in internal energy on mixing (noting that since there is no change in volume, ∆E =
∆H): mix ABH N E∆ = 1
2
( )AB AA BBE E E E= − +Where
E<0 → ∆Hmix negative
Sign of E E= 0 → ∆Hmix is zero
AB bonds are preferred over AA or BB bonds
Ideal solution (no difference between AA, AB or BB bonds
E>0 → ∆Hmix is positive AB bonds less preferred over AA or BB bonds
Three scenarios are possible regarding the sign of E

The equation in the case of the ideal solution for NAB can still be used as
an approximation
E= 0 → ∆Hmix is zero Ideal solution (no difference between AA, AB or BB bonds
For an ideal solution it can be shown that: 0AB A BN z N X X= N0 → Avogadro’s No.
z → No. of bonds per atom
E is not too negative or E is not too positive
Let us consider the scenarios a little further
If
If
0AB A BN z N X X=
0mix A B A BH z N X X E X X∆ = = ΩThis implies: mix A BH X X∆ = Ω 0z N EΩ =
( ) ( ln ln )
mix mix
mix A B A A B Bregular solution
H T S
G X X RT X X X X
∆ − ∆
∆ = Ω + +
14243 14444244443
1
2
( )AB AA BBE E E E= − +
This implies that for regular solutions Ω is the key parameter determining the behaviour of the
regular solution (Ω in turn depends on E, which is ‘some’ measure of the relative values of AA
and AB bond energies).
This implies that for regular solutions Ω is the key parameter determining the behaviour of the
regular solution (Ω in turn depends on E, which is ‘some’ measure of the relative values of AA
and AB bond energies).

The effect of Ω (& T)The effect of Ω (& T)
High T
Low T
Ω < 0 Ω > 0
We will
understand
these figures
in the coming
slides
Could be –T or ‘nothing’
Could be H, S or G

Understanding the G- composition curves: General aspects
∆ is obviously zero for
pure (unmixed) components
∆ is obviously zero for
pure (unmixed) components
As mixing leads to an increase in
entropy and T is always positive
(in K) –T∆Smix term is always
negative
As mixing leads to an increase in
entropy and T is always positive
(in K) –T∆Smix term is always
negative
The ∆Smix term only depends on
the composition for a random solid
solution
The ∆Smix term only depends on
the composition for a random solid
solution
The Ω parameter determines
the sign of the ∆Hmix
The Ω parameter determines
the sign of the ∆Hmix
The ∆Gmix is determined just by the
addition of the ∆Hmix & –T∆Smix for
each composition
The ∆Gmix is determined just by the
addition of the ∆Hmix & –T∆Smix for
each composition

Ω < 0
High T
Low T
 As ∆Hmix & –T∆Smix are both negative
∆Gmix is always negative.
 ∆Gmix gets more negative with
increasing T due to the –T∆Smix.
 As ∆Hmix & –T∆Smix are both negative
∆Gmix is always negative.
 ∆Gmix gets more negative with
increasing T due to the –T∆Smix.
Hsolution < Hpure components
Hsolution < Hpure components

High T
Low T
Ω > 0
Hsolution > Hpure components
Hsolution > Hpure components
∆Hmix and –T∆Smix oppose each
other at high ‘enough’ T, –T∆Smix
wins at all compositions and ∆Gmix
is always negative
∆Hmix and –T∆Smix oppose each
other at high ‘enough’ T, –T∆Smix
wins at all compositions and ∆Gmix
is always negative
At ‘low’ T, ∆Hmix wins over –T∆Smix
for some compositions (in the
‘middle’) and ∆Gmix turns positive for
this range of compositions.
At ‘low’ T, ∆Hmix wins over –T∆Smix
for some compositions (in the
‘middle’) and ∆Gmix turns positive for
this range of compositions.
Except at absolute zero (T), ∆Gmix
always decreases on the addition of a
small amount of solute (even if ∆Hmix
gets ‘very’ positive).
Except at absolute zero (T), ∆Gmix
always decreases on the addition of a
small amount of solute (even if ∆Hmix
gets ‘very’ positive).
 The phase diagram of such a system will show
complete solubility at high T and phase
separation for a range of compositions (in the
middle) at low T.
 The phase diagram of such a system will show
complete solubility at high T and phase
separation for a range of compositions (in the
middle) at low T.

Basics of thermodynamics

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Basics of thermodynamics