CHAPTER 6
Additional Topics in Trigonometry
1
2
INFORMATION – Wednesday 26th July 2017
•Lecture on Thursday 27 July on par. 6.5
(continue).
•No Lecture on Wednesday 9 August due to the
Public Holiday.
•Lecture on Thursday 10 August on par. 10.2.
•Class Test 1 scheduled for Thursday 3 August
on par. 6.5.
•No Tutorial on Thursday 5th October (Follows a
Monday Timetable)
6.5
Trigonometric Form of
a Complex Number
4
4
Objectives
►Definition of Polar Coordinates
►Relationship Between Polar and
Rectangular Coordinates
►Graphing Complex Numbers
►Polar Form of Complex Numbers
►De Moivre’s Theorem
►nth Roots of Complex Numbers
5
Definition of Polar Coordinates
6
Definition of Polar Coordinates
The polar coordinate system uses distances and
directions to specify the location of a point in the
plane.
To set up this system, we choose a fixed point O in
the plane called the pole (or origin) and draw from O
a ray (half-line) called the polar axis as in the figure.
7
Definition of Polar Coordinates
Then each point P can be assigned polar coordinates
P(r, ) where
r is the distance from O to P
 is the angle between the polar axis and the
segment
We use the convention that  is positive if measured
in a counterclockwise direction from the polar axis or
negative if measured in a clockwise direction.
8
Definition of Polar Coordinates
If r is negative, then P(r, ) is defined to be the point that
lies |r| units from the pole in the direction opposite to that
given by  .
9
Example 1 – Plotting Points in Polar Coordinates
Plot the points whose polar coordinates are given.
(a) (1, 3/4) (b) (3, –/6) (c) (3, 3) (d) ( –4, /4)
Solution:
The points are plotted.
(a) (b) (c) (d)
10
Example 1 – Solution
Note that the point in part (d) lies 4 units
from the origin along the angle 5 /4,
because the given value of r is negative.
cont’d
11
Relationship Between Polar
and Rectangular Coordinates
12
Relationship Between Polar and Rectangular Coordinates
The connection between the two systems is
illustrated in the figure, where the polar axis
coincides with the positive x-axis.
13
Relationship Between Polar and Rectangular Coordinates
The formulas are obtained from the figure using the
definitions of the trigonometric functions and the
Pythagorean Theorem.
14
Example 2 – Converting Polar Coordinates to Rectangular Coordinates
15
Relationship Between Polar and Rectangular Coordinates
Note that the equations relating polar and
rectangular coordinates do not uniquely
determine r or .
When we use these equations to find the
polar coordinates of a point, we must be
careful that the values we choose for r and 
give us a point in the correct quadrant.
16
Graphing Complex Numbers
17
Graphing Complex Numbers
To graph real numbers or sets of real numbers, we
have been using the number line, which has just one
dimension.
Complex numbers, however, have two components: a
real part and an imaginary part.
This suggests that we need two axes to graph
complex numbers: one for the real part and one for
the imaginary part. We call these the real axis and
the imaginary axis, respectively.
The plane determined by these two axes is called the
complex plane.
18
Graphing Complex Numbers
To graph the complex number a + bi, we plot the
ordered pair of numbers (a, b) in this plane, as
indicated.
19
Example 3 – Graphing Complex Numbers
Graph the complex numbers z1 = 2 + 3i, z2 = 3 – 2i, and
z1 + z2.
Solution:
We have
z1 + z2 = (2 + 3i) + (3 – 2i)
= 5 + i.
The graph is shown.
20
Graphing Complex Numbers
We define absolute value for complex numbers in a
similar fashion. Using the Pythagorean Theorem, we
can see from the figure that the distance between
a + bi and the origin in the complex plane is .
21
Graphing Complex Numbers
This leads to the following definition.
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Example 4 – Calculating the Modulus
Find the moduli of the complex numbers 3 + 4i and 8 – 5i.
Solution:
|3 + 4i| =
=
= 5
|8 – 5i| =
=
23
Polar Form of Complex Numbers
24
Polar Form of Complex Numbers
Let z = a + bi be a complex number, and in the
complex plane let’s draw the line segment joining the
origin to the point a + bi .
The length of this line segment is r = | z | = .
25
Polar Form of Complex Numbers
If  is an angle in standard position whose
terminal side coincides with this line segment,
then by the definitions of sine and cosine
a = r cos  and b = r sin 
so
z = r cos  + ir sin  = r (cos  + i sin )
26
Polar Form of Complex Numbers
We have shown the following.
27
Example 5 – Writing Complex Numbers in Polar Form
Write each complex number in polar form.
(a) 1 + i
(b) –1 +
(c) –4 – 4i
(d) 3 + 4i
28
Example 5 – Solution
These complex numbers are graphed, which
helps us find their arguments.
(a) (b) (c) (d)
29
Example 5(a) – Solution
An argument is  = /4 and r = = .
Thus
30
Example 5(b) – Solution
An argument is  = 2/3 and r = = 2.
Thus
cont’d
31
Example 5(c) – Solution
An argument is  = 7/6 (or we could use  = –5/6),
and r = = 8.
Thus
cont’d
32
Example 5(d) – Solution
An argument is  = tan–1 and r = = 5.
So
3 + 4i = 5
cont’d
33
Polar Form of Complex Numbers
This theorem says:
To multiply two complex numbers, multiply the
moduli and add the arguments
To divide two complex numbers, divide the moduli and
subtract the arguments.
34
Example 6 – Multiplying and Dividing Complex Numbers
Let
and
Find (a) z1z2 and (b) z1/z2.
Solution:
(a) By the Multiplication Formula
35
Example 6 – Solution
To approximate the answer, we use a calculator in radian
mode and get
z1z2  10(–0.2588 + 0.9659i)
= –2.588 + 9.659i
cont’d
36
Example 6 – Solution
(b) By the Division Formula
cont’d
37
Example 6 – Solution
Using a calculator in radian mode, we get the
approximate answer:
cont’d
38
De Moivre’s Theorem
39
De Moivre’s Theorem
Repeated use of the Multiplication Formula gives the
following useful formula for raising a complex number
to a power n for any positive integer n.
This theorem says:
To take the nth power of a complex number, we
take the nth power of the modulus and multiply
the argument by n.
40
Example 7 – Finding a Power Using De Moivre’s Theorem
Find .
Solution:
Since , it follows from Example 5(a) that
So by De Moivre’s Theorem
41
Example 7 – Solution cont’d
42
nth Roots of Complex Numbers
43
nth Roots of Complex Numbers
An nth root of a complex number z is any complex
number w such that wn = z.
De Moivre’s Theorem gives us a method for
calculating the nth roots of any complex number.
44
nth Roots of Complex Numbers
45
Example 8 – Finding Roots of a Complex Number
Find the six sixth roots of z = –64, and graph these roots in
the complex plane.
Solution:
In polar form z = 64(cos  + i sin  ). Applying the formula
for nth roots with n = 6, we get
for k = 0, 1, 2, 3, 4, 5.
46
Example 8 – Solution
Using 641/6 = 2, we find that the six sixth roots of –64 are
cont’d
47
Example 8 – Solution cont’d
48
Example 8 – Solution
All these points lie on a circle of radius 2, as shown.
cont’d
The six sixth roots of z = –64
49
nth Roots of Complex Numbers
When finding roots of complex numbers, we sometimes
write the argument  of the complex number in degrees.
In this case the nth roots are obtained from the formula
for k = 0, 1, 2, . . . , n – 1.

Complex numbers precalculus

  • 1.
    CHAPTER 6 Additional Topicsin Trigonometry 1
  • 2.
    2 INFORMATION – Wednesday26th July 2017 •Lecture on Thursday 27 July on par. 6.5 (continue). •No Lecture on Wednesday 9 August due to the Public Holiday. •Lecture on Thursday 10 August on par. 10.2. •Class Test 1 scheduled for Thursday 3 August on par. 6.5. •No Tutorial on Thursday 5th October (Follows a Monday Timetable)
  • 3.
  • 4.
    4 Objectives ►Definition of PolarCoordinates ►Relationship Between Polar and Rectangular Coordinates ►Graphing Complex Numbers ►Polar Form of Complex Numbers ►De Moivre’s Theorem ►nth Roots of Complex Numbers
  • 5.
  • 6.
    6 Definition of PolarCoordinates The polar coordinate system uses distances and directions to specify the location of a point in the plane. To set up this system, we choose a fixed point O in the plane called the pole (or origin) and draw from O a ray (half-line) called the polar axis as in the figure.
  • 7.
    7 Definition of PolarCoordinates Then each point P can be assigned polar coordinates P(r, ) where r is the distance from O to P  is the angle between the polar axis and the segment We use the convention that  is positive if measured in a counterclockwise direction from the polar axis or negative if measured in a clockwise direction.
  • 8.
    8 Definition of PolarCoordinates If r is negative, then P(r, ) is defined to be the point that lies |r| units from the pole in the direction opposite to that given by  .
  • 9.
    9 Example 1 –Plotting Points in Polar Coordinates Plot the points whose polar coordinates are given. (a) (1, 3/4) (b) (3, –/6) (c) (3, 3) (d) ( –4, /4) Solution: The points are plotted. (a) (b) (c) (d)
  • 10.
    10 Example 1 –Solution Note that the point in part (d) lies 4 units from the origin along the angle 5 /4, because the given value of r is negative. cont’d
  • 11.
    11 Relationship Between Polar andRectangular Coordinates
  • 12.
    12 Relationship Between Polarand Rectangular Coordinates The connection between the two systems is illustrated in the figure, where the polar axis coincides with the positive x-axis.
  • 13.
    13 Relationship Between Polarand Rectangular Coordinates The formulas are obtained from the figure using the definitions of the trigonometric functions and the Pythagorean Theorem.
  • 14.
    14 Example 2 –Converting Polar Coordinates to Rectangular Coordinates
  • 15.
    15 Relationship Between Polarand Rectangular Coordinates Note that the equations relating polar and rectangular coordinates do not uniquely determine r or . When we use these equations to find the polar coordinates of a point, we must be careful that the values we choose for r and  give us a point in the correct quadrant.
  • 16.
  • 17.
    17 Graphing Complex Numbers Tograph real numbers or sets of real numbers, we have been using the number line, which has just one dimension. Complex numbers, however, have two components: a real part and an imaginary part. This suggests that we need two axes to graph complex numbers: one for the real part and one for the imaginary part. We call these the real axis and the imaginary axis, respectively. The plane determined by these two axes is called the complex plane.
  • 18.
    18 Graphing Complex Numbers Tograph the complex number a + bi, we plot the ordered pair of numbers (a, b) in this plane, as indicated.
  • 19.
    19 Example 3 –Graphing Complex Numbers Graph the complex numbers z1 = 2 + 3i, z2 = 3 – 2i, and z1 + z2. Solution: We have z1 + z2 = (2 + 3i) + (3 – 2i) = 5 + i. The graph is shown.
  • 20.
    20 Graphing Complex Numbers Wedefine absolute value for complex numbers in a similar fashion. Using the Pythagorean Theorem, we can see from the figure that the distance between a + bi and the origin in the complex plane is .
  • 21.
    21 Graphing Complex Numbers Thisleads to the following definition.
  • 22.
    22 Example 4 –Calculating the Modulus Find the moduli of the complex numbers 3 + 4i and 8 – 5i. Solution: |3 + 4i| = = = 5 |8 – 5i| = =
  • 23.
    23 Polar Form ofComplex Numbers
  • 24.
    24 Polar Form ofComplex Numbers Let z = a + bi be a complex number, and in the complex plane let’s draw the line segment joining the origin to the point a + bi . The length of this line segment is r = | z | = .
  • 25.
    25 Polar Form ofComplex Numbers If  is an angle in standard position whose terminal side coincides with this line segment, then by the definitions of sine and cosine a = r cos  and b = r sin  so z = r cos  + ir sin  = r (cos  + i sin )
  • 26.
    26 Polar Form ofComplex Numbers We have shown the following.
  • 27.
    27 Example 5 –Writing Complex Numbers in Polar Form Write each complex number in polar form. (a) 1 + i (b) –1 + (c) –4 – 4i (d) 3 + 4i
  • 28.
    28 Example 5 –Solution These complex numbers are graphed, which helps us find their arguments. (a) (b) (c) (d)
  • 29.
    29 Example 5(a) –Solution An argument is  = /4 and r = = . Thus
  • 30.
    30 Example 5(b) –Solution An argument is  = 2/3 and r = = 2. Thus cont’d
  • 31.
    31 Example 5(c) –Solution An argument is  = 7/6 (or we could use  = –5/6), and r = = 8. Thus cont’d
  • 32.
    32 Example 5(d) –Solution An argument is  = tan–1 and r = = 5. So 3 + 4i = 5 cont’d
  • 33.
    33 Polar Form ofComplex Numbers This theorem says: To multiply two complex numbers, multiply the moduli and add the arguments To divide two complex numbers, divide the moduli and subtract the arguments.
  • 34.
    34 Example 6 –Multiplying and Dividing Complex Numbers Let and Find (a) z1z2 and (b) z1/z2. Solution: (a) By the Multiplication Formula
  • 35.
    35 Example 6 –Solution To approximate the answer, we use a calculator in radian mode and get z1z2  10(–0.2588 + 0.9659i) = –2.588 + 9.659i cont’d
  • 36.
    36 Example 6 –Solution (b) By the Division Formula cont’d
  • 37.
    37 Example 6 –Solution Using a calculator in radian mode, we get the approximate answer: cont’d
  • 38.
  • 39.
    39 De Moivre’s Theorem Repeateduse of the Multiplication Formula gives the following useful formula for raising a complex number to a power n for any positive integer n. This theorem says: To take the nth power of a complex number, we take the nth power of the modulus and multiply the argument by n.
  • 40.
    40 Example 7 –Finding a Power Using De Moivre’s Theorem Find . Solution: Since , it follows from Example 5(a) that So by De Moivre’s Theorem
  • 41.
    41 Example 7 –Solution cont’d
  • 42.
    42 nth Roots ofComplex Numbers
  • 43.
    43 nth Roots ofComplex Numbers An nth root of a complex number z is any complex number w such that wn = z. De Moivre’s Theorem gives us a method for calculating the nth roots of any complex number.
  • 44.
    44 nth Roots ofComplex Numbers
  • 45.
    45 Example 8 –Finding Roots of a Complex Number Find the six sixth roots of z = –64, and graph these roots in the complex plane. Solution: In polar form z = 64(cos  + i sin  ). Applying the formula for nth roots with n = 6, we get for k = 0, 1, 2, 3, 4, 5.
  • 46.
    46 Example 8 –Solution Using 641/6 = 2, we find that the six sixth roots of –64 are cont’d
  • 47.
    47 Example 8 –Solution cont’d
  • 48.
    48 Example 8 –Solution All these points lie on a circle of radius 2, as shown. cont’d The six sixth roots of z = –64
  • 49.
    49 nth Roots ofComplex Numbers When finding roots of complex numbers, we sometimes write the argument  of the complex number in degrees. In this case the nth roots are obtained from the formula for k = 0, 1, 2, . . . , n – 1.