Name :- Suraj.B.Rawat -Suraj.B.Rawat -140410109085140410109085
Smit Shah -Smit Shah -140410109096140410109096
S.Y electrical 2S.Y electrical 2
Sem 3Sem 3
Subject:-Circuits and NetworksCircuits and Networks
Topic :-Initial ConditionsInitial Conditions
INITIAL CONDITIONSINITIAL CONDITIONS :: ImportanceImportance
• Differential Equations written for a network
may contain arbitrary constants equal to the
order of the differential equations.
• The reason for studying initial conditions is to
find the value of arbitrary constants that
appear in the general solution of differential
equations written for a given network.
• In Initial conditions, we find the change in
selected variables in a circuit when one or
more switches are moved from open to
closed positions or vice versa.
t=0-
indicates the time just before changing
the position of the switch.
t=0 indicates the time when the position of
switch is changed.
t=0+
indicates the time immediately after
changing the position of switch.
• Initial condition focuses solely on the current
and voltages of energy storing elements
(inductor and capacitor) as they will
determine the circuit behavior at t>0.
• PAST HISTORY OF THE CIRCUIT WILL
SHOW UP THE CAPACITOR VOLTAGES
AND INDUCTOR CURRENTS.
1.1. RESISTORRESISTOR
 The voltage current relation of an ideal
resistance is
V=R*I
 From this equation it can be concluded that
the instantaneous current flowing through
the resistor changes if the instantaneous
voltage across it changes & vice versa.
 The past voltage or current values have no
effect on the present or future working of the
resistor i.e.. It’s resistance remains the same
irrespective of the past conditions
2.. INDUCTORINDUCTOR
 The expression for current through the
inductor is given by
Hence if i(0-
)=0A , then i(0+
)=0A
So we can visualize inductor as a open
circuit at t=0+
• If i(0-
)=I0 , then i(0+
)=I0 i.e. the inductor can
be thought as a current source of I0 as
shown
FINAL CONDITIONS :FINAL CONDITIONS :
 From the basic relationship
V= L*(di/dt)
We can state that V=0 in steady state
conditions at t= as (di/dt)=0 due to
constant current
3. CAPACITORCAPACITOR
 The expression for voltage across the
capacitor is given by
If V(0-
)=0V , then V(0+
)=0V indicating the
capacitor as a short circuit
If V(0-
)= V volts, then the capacitor can be
visualized as a voltage source of V volts
• Final ConditionsFinal Conditions
The current across the capacitor is given by
the equation
i=C*(dv/dt)
which indicates that i=0A in steady state at t=
due to capacitor being fully charged.
EXAMPLE-1 : In the network shown in the
figure the switch is closed at t=0. Determine i,
(di/dt) and (d2
i/dt2
) at t=0+
.
At t=0-
, the switch is
Closed. Due to which
il(0-
)=0A
Vc(0-
)=0V
At t=0+
the circuit is
From the circuit
il(0+
)=0A
Vc(0+
)=0V
• Writing KVL clockwise for the circuit
Putting t=0+
in equation (2)
• Differentiating equation (1) with respect to
time
THANK YOU
Thermocouples 18

Initial Conditions

  • 1.
    Name :- Suraj.B.Rawat-Suraj.B.Rawat -140410109085140410109085 Smit Shah -Smit Shah -140410109096140410109096 S.Y electrical 2S.Y electrical 2 Sem 3Sem 3 Subject:-Circuits and NetworksCircuits and Networks Topic :-Initial ConditionsInitial Conditions
  • 2.
    INITIAL CONDITIONSINITIAL CONDITIONS:: ImportanceImportance • Differential Equations written for a network may contain arbitrary constants equal to the order of the differential equations. • The reason for studying initial conditions is to find the value of arbitrary constants that appear in the general solution of differential equations written for a given network.
  • 3.
    • In Initialconditions, we find the change in selected variables in a circuit when one or more switches are moved from open to closed positions or vice versa. t=0- indicates the time just before changing the position of the switch. t=0 indicates the time when the position of switch is changed. t=0+ indicates the time immediately after changing the position of switch.
  • 4.
    • Initial conditionfocuses solely on the current and voltages of energy storing elements (inductor and capacitor) as they will determine the circuit behavior at t>0. • PAST HISTORY OF THE CIRCUIT WILL SHOW UP THE CAPACITOR VOLTAGES AND INDUCTOR CURRENTS.
  • 5.
    1.1. RESISTORRESISTOR  Thevoltage current relation of an ideal resistance is V=R*I  From this equation it can be concluded that the instantaneous current flowing through the resistor changes if the instantaneous voltage across it changes & vice versa.  The past voltage or current values have no effect on the present or future working of the resistor i.e.. It’s resistance remains the same irrespective of the past conditions
  • 6.
    2.. INDUCTORINDUCTOR  Theexpression for current through the inductor is given by
  • 7.
    Hence if i(0- )=0A, then i(0+ )=0A So we can visualize inductor as a open circuit at t=0+
  • 8.
    • If i(0- )=I0, then i(0+ )=I0 i.e. the inductor can be thought as a current source of I0 as shown
  • 9.
    FINAL CONDITIONS :FINALCONDITIONS :  From the basic relationship V= L*(di/dt) We can state that V=0 in steady state conditions at t= as (di/dt)=0 due to constant current
  • 10.
    3. CAPACITORCAPACITOR  Theexpression for voltage across the capacitor is given by
  • 11.
    If V(0- )=0V ,then V(0+ )=0V indicating the capacitor as a short circuit
  • 12.
    If V(0- )= Vvolts, then the capacitor can be visualized as a voltage source of V volts
  • 13.
    • Final ConditionsFinalConditions The current across the capacitor is given by the equation i=C*(dv/dt) which indicates that i=0A in steady state at t= due to capacitor being fully charged.
  • 14.
    EXAMPLE-1 : Inthe network shown in the figure the switch is closed at t=0. Determine i, (di/dt) and (d2 i/dt2 ) at t=0+ . At t=0- , the switch is Closed. Due to which il(0- )=0A Vc(0- )=0V
  • 15.
    At t=0+ the circuitis From the circuit il(0+ )=0A Vc(0+ )=0V
  • 16.
    • Writing KVLclockwise for the circuit Putting t=0+ in equation (2)
  • 17.
    • Differentiating equation(1) with respect to time
  • 18.