Inline function in C++

Dec 1, 2014Download as pptx, pdf

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Inline functions in C++ allow the compiler to paste the function code directly where the function is called, rather than generating a call to a function definition elsewhere. Inline functions can improve performance by reducing compilation time and function call overhead. However, functions containing loops may not be expanded inline and will generate a warning, as loop variables have dynamic rather than static values. To resolve this, the function can be declared outside the class using the scope resolution operator.

What is Inline Function in C++
• Inline Function is a Inbuilt Function in C++ .
• Those function which are declared inside the class are automatically
defined as INLINE.
• The function which are static means the values of the variables inside
the function are not dynamic only those function will be accepted by
inline function else the warning will be occurred by the C compiler..
• Eg. Looping statement are not considered in the Inline Function…

How to declare the inline function in the program?
inline <prototype> <function name>(argument 1,argument 2)
inline void sum( int a , int b)

Most read

Advantages….
• The compiler makes a copy of the function defined as the inline so that
The compilation time is reduced as the compiler does not have to
recompile that part of the code.
• Due to this the static values are only be favorable to the rules of the
inline function
• If the function contains looping statement means the values are not fixed
because up to which values loop will continue.
• Thus if the operation or function is of adding of 2 values are appropriate for
the inline function because here the values of variables are dynamic but the
operation is only same i.e. SUM(+)

Inline function warning in C++
• As I stated above compiler gives warning when you insert any
looping statement in the inline function.
Warning:
FUNCTION CONTAINING FOR ARE NOT EXPANDED INLINE
Solving this warning…
• The solution is just declare the function outside the class.. Using the scope resolution
operator. (::)

EG
#include<conio.h>
#include<iostream.h>
class loop
{
int a;
public:
inline void even();
};
void loop ::even(int aa)
{
a= aa;
for(int i =1; i<=a; i++)
{
if(i%2==0)
{
printf(“nn %d”,i);
}
}
}

void main()
{
int a;
clrscr();
printf(“nn Please enter the number : ”);
scanf(“%d”,&a);
loop l1;
l1.even(a);
getch();
}

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Inline function in C++

1. What is Inline Function in C++ • Inline Function is a Inbuilt Function in C++ . • Those function which are declared inside the class are automatically defined as INLINE. • The function which are static means the values of the variables inside the function are not dynamic only those function will be accepted by inline function else the warning will be occurred by the C compiler.. • Eg. Looping statement are not considered in the Inline Function…

2. How to declare the inline function in the program? inline <prototype> <function name>(argument 1,argument 2) inline void sum( int a , int b)

3. Advantages…. • The compiler makes a copy of the function defined as the inline so that The compilation time is reduced as the compiler does not have to recompile that part of the code. • Due to this the static values are only be favorable to the rules of the inline function • If the function contains looping statement means the values are not fixed because up to which values loop will continue. • Thus if the operation or function is of adding of 2 values are appropriate for the inline function because here the values of variables are dynamic but the operation is only same i.e. SUM(+)

4. Inline function warning in C++ • As I stated above compiler gives warning when you insert any looping statement in the inline function. Warning: FUNCTION CONTAINING FOR ARE NOT EXPANDED INLINE Solving this warning… • The solution is just declare the function outside the class.. Using the scope resolution operator. (::)

5. EG #include<conio.h> #include<iostream.h> class loop { int a; public: inline void even(); }; void loop ::even(int aa) { a= aa; for(int i =1; i<=a; i++) { if(i%2==0) { printf(“nn %d”,i); } } }

6. void main() { int a; clrscr(); printf(“nn Please enter the number : ”); scanf(“%d”,&a); loop l1; l1.even(a); getch(); }

Inline function in C++

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