OBJECTIVES
•ILLUSTRATE THE FOLLOWING MEASURES OF
POSITION: QUARTILES, DECILES AND PERCENTILES
•CALCULATE SPECIFIED MEASURE OF POSITION (E.G.
90TH PERCENTILE) OF A SET OF DATA.
QUARTILE FOR GROUPED DATA
•THE QUARTILES ARE THE SCORE POINTS WHICH
DIVIDE A DISTRIBUTION INTO FOUR EQUAL PARTS.
THE QUARTILE FOR GROUPED DATA
1. THE FOLLOWING FORMULA IS USED IN FINDING THE QUARTILES
OF GROUPED DATA
kN
cfb-
Qk = LB +
4
FQK[ ]i
Where: LB = lower boundary of Qk class
N = total frequency
cfb = cumulative frequency of the
class before the Qk class
FQk = frequency of the Qk class
i = size of the class interval
k = nth quartile, where n = 1, 2, and 3
THE MEASURE OF POSITION
QUARTILE FOR GROUPED DATA
2. FORMULA TO CALCULATE THE QK CLASS
Qk class=
kN
4
Where: N = total frequency
k = nth quartile, where n = 1, 2, and 3
THE MEASURE OF POSITION
QUARTILE FOR GROUPED DATA
EXAMPLE
CALCULATE THE Q1, Q2, AND Q3 IF THE MATHEMATICS TEST SCORES
OF 50 STUDENTS
SCORES FREQUENCY
46-50 4
41-45 8
36-40 11
31-35 9
26-30 12
21-25 6
THE MEASURE OF POSITION
QUARTILE FOR GROUPED DATA
STEP 1.A: DETERMINE THE LOWER BOUNDARIES
SCORES FREQUENCY Lower Boundaries
(LB)
46-50 4
41-45 8
36-40 11
31-35 9
26-30 12 25.5
21-25 6 20.5
To solve for LB
subtract 0.5 to the
smallest number per
class interval
21 – 0.5 = 20.5
30.5
35.5
40.5
45.5
THE MEASURE OF POSITION
QUARTILE FOR GROUPED DATA
STEP 1.B: DETERMINE THE CUMULATIVE FREQUENCY
SCORES FREQUENCY Lower Boundaries
(LB)
Less than
Cumulative
Frequency (<cf)
46-50 4 45.5
41-45 8 40.5
36-40 11 35.5
31-35 9 30.5 27
26-30 12 25.5 18
21-25 6 20.5 6 Copied from the frequency
6 + the frequency of the class interval
18 + the frequency of the class interval
38
46
50
THE MEASURE OF POSITION
QUARTILE FOR GROUPED DATA
Q1 class=
N
4
STEP 2.A: CALCULATE THE Q1 CLASS
N = 50 k = 1Given:
Q1 class =
50
4
=12.5
This means that we need to find the class interval where
the 12.5th score is contained
THE MEASURE OF POSITION
QUARTILE FOR GROUPED DATA
STEP 2.B: LOCATE THE CLASS INTERVAL WHERE THE Q1
CLASS IS SITUATED
SCORES FREQUENCY Lower Boundaries
(LB)
Less thanCumulative
Frequency (<cf)
46-50 4 45.5 50
41-45 8 40.5 46
36-40 11 35.5 38
31-35 9 30.5 27
26-30 12 25.5 18
21-25 6 20.5 6
(7th to 18th score)
Q1 class
The Q1 class is class interval 26-30
N = 50
cfb = 6
fQ1 = 12
LB = 25.5
i = 5
Σ f = 50
Cfb =
fQ1 = LB =
i = 5
THE MEASURE OF POSITION
QUARTILE FOR GROUPED DATA
STEP 2: SOLVE Q1 USING THE FORMULA
N
cfb-
Q1 = LB +
4
FQ1[ ]i
N = 50
cfb = 6
fQ1 = 12
LB = 25.5
i = 5
THE MEASURE OF POSITION
QUARTILE FOR GROUPED DATA
Therefore, 25% of the students have a score less than or equal to 28.21
50
6-
Q1 = 25.5 + 4
12[ ]5
Given: N = 50
cfb = 6
fQ1 = 12
LB = 25.5
i = 5
Q1 = 28.21 Final answer
OBJECTIVES
•ILLUSTRATE THE FOLLOWING MEASURES OF
POSITION: QUARTILES, DECILES AND PERCENTILES
•CALCULATE SPECIFIED MEASURE OF POSITION (E.G.
90TH PERCENTILE) OF A SET OF DATA.
THANK YOU
EDUCATIONAL PROJAMS

QUARTILES : MEASURES OF POSITION FOR GROUPED DATA

  • 2.
    OBJECTIVES •ILLUSTRATE THE FOLLOWINGMEASURES OF POSITION: QUARTILES, DECILES AND PERCENTILES •CALCULATE SPECIFIED MEASURE OF POSITION (E.G. 90TH PERCENTILE) OF A SET OF DATA.
  • 3.
    QUARTILE FOR GROUPEDDATA •THE QUARTILES ARE THE SCORE POINTS WHICH DIVIDE A DISTRIBUTION INTO FOUR EQUAL PARTS.
  • 4.
    THE QUARTILE FORGROUPED DATA 1. THE FOLLOWING FORMULA IS USED IN FINDING THE QUARTILES OF GROUPED DATA kN cfb- Qk = LB + 4 FQK[ ]i Where: LB = lower boundary of Qk class N = total frequency cfb = cumulative frequency of the class before the Qk class FQk = frequency of the Qk class i = size of the class interval k = nth quartile, where n = 1, 2, and 3
  • 5.
    THE MEASURE OFPOSITION QUARTILE FOR GROUPED DATA 2. FORMULA TO CALCULATE THE QK CLASS Qk class= kN 4 Where: N = total frequency k = nth quartile, where n = 1, 2, and 3
  • 6.
    THE MEASURE OFPOSITION QUARTILE FOR GROUPED DATA EXAMPLE CALCULATE THE Q1, Q2, AND Q3 IF THE MATHEMATICS TEST SCORES OF 50 STUDENTS SCORES FREQUENCY 46-50 4 41-45 8 36-40 11 31-35 9 26-30 12 21-25 6
  • 7.
    THE MEASURE OFPOSITION QUARTILE FOR GROUPED DATA STEP 1.A: DETERMINE THE LOWER BOUNDARIES SCORES FREQUENCY Lower Boundaries (LB) 46-50 4 41-45 8 36-40 11 31-35 9 26-30 12 25.5 21-25 6 20.5 To solve for LB subtract 0.5 to the smallest number per class interval 21 – 0.5 = 20.5 30.5 35.5 40.5 45.5
  • 8.
    THE MEASURE OFPOSITION QUARTILE FOR GROUPED DATA STEP 1.B: DETERMINE THE CUMULATIVE FREQUENCY SCORES FREQUENCY Lower Boundaries (LB) Less than Cumulative Frequency (<cf) 46-50 4 45.5 41-45 8 40.5 36-40 11 35.5 31-35 9 30.5 27 26-30 12 25.5 18 21-25 6 20.5 6 Copied from the frequency 6 + the frequency of the class interval 18 + the frequency of the class interval 38 46 50
  • 9.
    THE MEASURE OFPOSITION QUARTILE FOR GROUPED DATA Q1 class= N 4 STEP 2.A: CALCULATE THE Q1 CLASS N = 50 k = 1Given: Q1 class = 50 4 =12.5 This means that we need to find the class interval where the 12.5th score is contained
  • 10.
    THE MEASURE OFPOSITION QUARTILE FOR GROUPED DATA STEP 2.B: LOCATE THE CLASS INTERVAL WHERE THE Q1 CLASS IS SITUATED SCORES FREQUENCY Lower Boundaries (LB) Less thanCumulative Frequency (<cf) 46-50 4 45.5 50 41-45 8 40.5 46 36-40 11 35.5 38 31-35 9 30.5 27 26-30 12 25.5 18 21-25 6 20.5 6 (7th to 18th score) Q1 class The Q1 class is class interval 26-30 N = 50 cfb = 6 fQ1 = 12 LB = 25.5 i = 5 Σ f = 50 Cfb = fQ1 = LB = i = 5
  • 11.
    THE MEASURE OFPOSITION QUARTILE FOR GROUPED DATA STEP 2: SOLVE Q1 USING THE FORMULA N cfb- Q1 = LB + 4 FQ1[ ]i N = 50 cfb = 6 fQ1 = 12 LB = 25.5 i = 5
  • 12.
    THE MEASURE OFPOSITION QUARTILE FOR GROUPED DATA Therefore, 25% of the students have a score less than or equal to 28.21 50 6- Q1 = 25.5 + 4 12[ ]5 Given: N = 50 cfb = 6 fQ1 = 12 LB = 25.5 i = 5 Q1 = 28.21 Final answer
  • 13.
    OBJECTIVES •ILLUSTRATE THE FOLLOWINGMEASURES OF POSITION: QUARTILES, DECILES AND PERCENTILES •CALCULATE SPECIFIED MEASURE OF POSITION (E.G. 90TH PERCENTILE) OF A SET OF DATA.
  • 14.