Here are the steps to solve this problem:
1. Given:
Conductor diameter (d) = 10.4 mm
Spacing between conductors (s) = 2.5 m
Air temperature (T) = 21°C = 294 K
Air pressure (P) = 73.6 cm of Hg = 9.6 kPa
Irregularity factor (K) = 0.85
Surface factor for local corona (K1) = 0.7
Surface factor for general corona (K2) = 0.8
2. Critical disruptive voltage (Vc) = 28√(sdP/K)
= 28√(10.4×10-3×2.5×