GOOD
MORNIN
G
UNIT 1 Overview
UNIT TITLE Quadratic Equations
KEY CONCEPT Form
RELATED CONCEPT Patterns, Space,
Equivalence
GLOBAL CONTEXT Scientific and technical innovation
STATEMENT OF INQUIRY Representing patterns with equivalent
forms can lead to better systems,
models and methods
ATL SKILLS Social Skills (Collaboration skills),
Research Skills (Information literacy skills)
SOLVING
QUADRATIC
EQUATONS
MATHEMATICS 9
A quadratic equation in one variable
is an equation of degree 2. The
standard form of a quadratic
equation is
,
where a, b, and c are real numbers,
and
Take note of this:
•a is the coefficient of (cannot be zero)
•b is the coefficient of x
•c is the constant term
Some examples of quadratic equations are
4𝑥2 − 1 = 0 = 0
= 0
𝑥2 − 6𝑥 = 0
Quadratic Equations may be written in
various forms.
50
Quadratic equations should
always be written in standard form
before solving, as this makes the
process simpler and more
organized.
Activity
Write each quadratic equation in standard
form and determine a, b, and c.
What is meant by finding
the solution of the
equation
4x + 6 =14?
Let's Recall
•Any value that satisfies an
equation is called a solution.
•The solution is also called
root.
In solving quadratic equations,
it means finding its solution(s) or
root(s) that will satisfy the given
equation.
WAYS of SOLVING QUADRATIC EQUATIONS
EXTRACTING THE SQUARE ROOT
FACTORISING
COMPLETING THE SQUARE
QUADRATIC FORMULA
Solving Quadratic
Equations by
Extracting the Square
Roots
Learning Objectives
determine the
roots of a
quadratic
equation by
extracting the
square roots
solve quadratic
equation by
extracting the
square roots
display accuracy
in solving
quadratic
equations by
extracting the
square roots
What is
Square
root?
Let's Recall
A number that
produces a specified
quantity when
multiplied by itself.
3)
Give the square roots of the following
numbers.
2) –
4) 5)
we usually use this
method to solve
for x when the quadratic
equations is in the form:
Square Root Property
Square Root Property
For any real number n
If and
then
Steps in Solving Quadratic Equations by Extracting
the Square Roots
1. Transform the given in the form of
2. Simplify the equation so that only the
term with variable remains on the left
side of that equation
3. Extract the roots of both sides
of the equation
4. Check your answer
𝟏 . 𝒙𝟐
− 𝟏𝟔 =𝟎
Examples:
𝟐 . 𝒙 𝟐
= 𝟎
𝟑 . 𝒙𝟐
− 𝟗= 𝟎
𝟒 . ( 𝒙 − 𝟒)𝟐
− 𝟐𝟓=𝟎
STEP 1: Transform the given in the form of
Example 1:
𝒙 𝟐
−𝟏𝟔=𝟎Apply Addition Property of Equality
𝒙𝟐
−𝟏𝟔+𝟏𝟔=𝟎+𝟏𝟔
𝒙 𝟐
=𝟏𝟔
Or simply transpose 16 to the other side
𝒙 𝟐
−𝟏𝟔=𝟎
𝒙 𝟐
=𝟏𝟔
Example 1:
Example 1:
STEP 2: Simplify the equation so that only the term
with variable remains on the left side of that equation
Example 1:
𝒙 𝟐
=𝟏𝟔
Example 1:
STEP 3: Extract the roots of both sides of the equation
Example 1:
𝒙 𝟐
=𝟏𝟔
√ 𝒙 𝟐
=± √𝟏𝟔
𝒙 =± 𝟒 ¿ 𝒙=+ 𝟒∧𝒙=−𝟒
Example 1:
STEP 4: Check your answer
Example 1:
𝒙=𝟒 𝒙=− 𝟒
Checking:
For
𝒙 𝟐
−𝟏𝟔=𝟎
(𝟒)𝟐
−𝟏𝟔=𝟎
𝟏𝟔−𝟏𝟔=𝟎
𝟎=𝟎
𝒙 𝟐
−𝟏𝟔=𝟎
For
(− 𝟒)𝟐
−𝟏𝟔=𝟎
𝟏𝟔−𝟏𝟔=𝟎
𝟎=𝟎
Both values of x satisfy the given equation.
So, the equation is true when x = 4 or when x= -4
Answer: The Equation has two solutions or roots: x= 4
or x= -4
Example 1:
Example 2:
𝒙 𝟐
= 𝟎
It is already in the form of
Answer: Since
Property No. 3
STEP 1: Transform the given in the form of
Example 1:
𝒙 𝟐
− 𝟗=𝟎Apply Addition Property of Equality
𝒙 𝟐
−𝟗+ 𝟗=𝟎+𝟗
𝒙 𝟐
=𝟗
Or simply transpose 9 to the other side
𝒙 𝟐
=𝟗
Example 1:
Example 3:
𝒙 𝟐
− 𝟗=𝟎
STEP 2: Simplify the equation so that only the term
with variable remains on the left side of that equation
𝒙 𝟐
=𝟗
Example 1:
Example 1:
Example 3:
Answer:
STEP 1: Transform the given in the form of
Example 1:
(𝒙 − 𝟒)𝟐
− 𝟐𝟓=𝟎 Apply Addition Property of Equality
(𝒙 − 𝟒)𝟐
− 𝟐𝟓+𝟐𝟓=𝟎+𝟐𝟓
( 𝒙 − 𝟒)𝟐
=𝟐𝟓
Or simply transpose -25 to the other side
Example 1:
Example 4:
(𝒙 − 𝟒)𝟐
− 𝟐𝟓=𝟎
(𝒙 − 𝟒)𝟐
=𝟐𝟓
STEP 3: Extract the roots of both sides of the equation
√(𝒙−𝟒)
𝟐
=±√𝟐𝟓
𝒙 − 𝟒=± 𝟓 ¿ 𝒙 − 𝟒=+𝟓∧𝒙 − 𝟒=− 𝟓
Example 1:
Example 1:
Example 4:
Answer: The Equation
has two solutions or roots: x= 9 or x= -1
Example 4:
SOLVE
Solve the following quadratic equation by
extracting the square root. Show your
solutions and box your final answer. (2
points each)
6.
7.
8.
9.
10.
Solving Quadratic
Equations by
Factorising
Learning Objectives
Identify the
roots of a
quadratic
equations by
factorising
solve quadratic
equation by
factorising
Show patience
and accuracy in
solving quadratic
equations by
factorising
Let's Recall
Solve the following equations.
Let’s play a game
we usually use this
method to solve
for x when the quadratic
equation is in the form:
Factorisation
Steps in Solving Quadratic Equations by Factorising
1. Write the quadratic equation in standard form.
Transform the given equation in the form:
2. Factor the quadratic expression on the left
side of the equation.
3. Apply the Zero Product Property by
equating the two factors of quadratic equation
to 0.
5. Check your answers.
4. Find the values of the variable by solving the
two equations
Zero Product Property
The product AB = 0, if and only if
A = 0 or B = 0.
How to Factor Quadratic Equations When
a=1
1. 𝑥 2
+6 𝑥 +8 =0
Examples:
3.
Factorize the given quadratic equation
x² + 6x + 8 = 0
STEP 1: Identify the values of b and c.
In this example, the values of b and c are: b=6 & c=8
STEP 2: Find two numbers that both ADD to b and
both MULTIPLY to c.
2 and 4 works since the sum of 2 and 4 is 6 and the
product of 2 and 4 is 8
STEP 3: Use your numbers from step two to write
out the factors and solve.
Continuation
Now we have a new equation:
•(x+4)(x+2)=0
This is not our final answer. To solve this quadratic by
factoring, we have to take each factor, set it equal to zero,
and solve to find our solutions as follows:
•x+4 = 0 x = -4
→
•x+2 = 0 x = -2
→
Summary
Activity
Solve the following quadratic equation by
factorising. Show your solutions and box
your final answer.
3. 4.
How to Factor Quadratic Equations When
a≠1
1. 3 𝑥2
+17 𝑥 +10=0
Examples:
3.
4.
Factorize the given quadratic equation
STEP 1: Identify the values of a,b and c.
In this example, the values of b and c are: a=3, b=17 &
c=10
STEP 2: Multiply a and c first and then find two
numbers that both ADD to b and both MULTIPLY to ac.
ac = 3(10)=30.
2 and 15 works since the sum of 2 and 15 is 17 and the
product of 2 and 15 is 30
continuation
STEP 3: factor and replace the middle term with the
two factors
↓
continuation
STEP 4: Split the new quadratic down the middle
and take the GCF of each side
↓
First Binomial: 3x² + 15x = 3x(x + 5)
First Binomial: 2x + 10 = 2(x +5)
continuation
STEP 4: Identify the Factors
↓
↓
3x(x + 5)
↓
(3x
Continuation
Now we have a new equation:
•(3x
This is not our final answer. To solve this quadratic by
factoring, we have to take each factor, set it equal to zero,
and solve to find our solutions as follows:
• 3x = 0 x = -2/3
→
• = 0 x = -5
→
Find the solution
of
Find the solution
of
2𝑥2 + 15𝑥 =
−27
Each group must pick a problem to solve and present
their answer to the class.
Find the solution
of
+ 7
Find the solution of
+ 3
Find the solution
of
Find the solution
of+ 5
1. What process are you going to use
in solving quadratic equations if
the given equations are in the form
of ?
2. What process are you going to use
in solving quadratic equations if
the given equations are in the form
of
for a =1 and a ≠1?
Generalizations:
Slides on factoring Quadratic equation for middle school

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Slides on factoring Quadratic equation for middle school

  • 2. UNIT 1 Overview UNIT TITLE Quadratic Equations KEY CONCEPT Form RELATED CONCEPT Patterns, Space, Equivalence GLOBAL CONTEXT Scientific and technical innovation STATEMENT OF INQUIRY Representing patterns with equivalent forms can lead to better systems, models and methods ATL SKILLS Social Skills (Collaboration skills), Research Skills (Information literacy skills)
  • 4. A quadratic equation in one variable is an equation of degree 2. The standard form of a quadratic equation is , where a, b, and c are real numbers, and
  • 5. Take note of this: •a is the coefficient of (cannot be zero) •b is the coefficient of x •c is the constant term
  • 6. Some examples of quadratic equations are 4𝑥2 − 1 = 0 = 0 = 0 𝑥2 − 6𝑥 = 0
  • 7. Quadratic Equations may be written in various forms. 50
  • 8. Quadratic equations should always be written in standard form before solving, as this makes the process simpler and more organized.
  • 9. Activity Write each quadratic equation in standard form and determine a, b, and c.
  • 10. What is meant by finding the solution of the equation 4x + 6 =14? Let's Recall
  • 11. •Any value that satisfies an equation is called a solution. •The solution is also called root. In solving quadratic equations, it means finding its solution(s) or root(s) that will satisfy the given equation.
  • 12. WAYS of SOLVING QUADRATIC EQUATIONS EXTRACTING THE SQUARE ROOT FACTORISING COMPLETING THE SQUARE QUADRATIC FORMULA
  • 14. Learning Objectives determine the roots of a quadratic equation by extracting the square roots solve quadratic equation by extracting the square roots display accuracy in solving quadratic equations by extracting the square roots
  • 16. A number that produces a specified quantity when multiplied by itself.
  • 17. 3) Give the square roots of the following numbers. 2) – 4) 5)
  • 18. we usually use this method to solve for x when the quadratic equations is in the form: Square Root Property
  • 19. Square Root Property For any real number n If and then
  • 20. Steps in Solving Quadratic Equations by Extracting the Square Roots 1. Transform the given in the form of 2. Simplify the equation so that only the term with variable remains on the left side of that equation 3. Extract the roots of both sides of the equation 4. Check your answer
  • 21. 𝟏 . 𝒙𝟐 − 𝟏𝟔 =𝟎 Examples: 𝟐 . 𝒙 𝟐 = 𝟎 𝟑 . 𝒙𝟐 − 𝟗= 𝟎 𝟒 . ( 𝒙 − 𝟒)𝟐 − 𝟐𝟓=𝟎
  • 22. STEP 1: Transform the given in the form of Example 1: 𝒙 𝟐 −𝟏𝟔=𝟎Apply Addition Property of Equality 𝒙𝟐 −𝟏𝟔+𝟏𝟔=𝟎+𝟏𝟔 𝒙 𝟐 =𝟏𝟔 Or simply transpose 16 to the other side 𝒙 𝟐 −𝟏𝟔=𝟎 𝒙 𝟐 =𝟏𝟔 Example 1: Example 1:
  • 23. STEP 2: Simplify the equation so that only the term with variable remains on the left side of that equation Example 1: 𝒙 𝟐 =𝟏𝟔 Example 1:
  • 24. STEP 3: Extract the roots of both sides of the equation Example 1: 𝒙 𝟐 =𝟏𝟔 √ 𝒙 𝟐 =± √𝟏𝟔 𝒙 =± 𝟒 ¿ 𝒙=+ 𝟒∧𝒙=−𝟒 Example 1:
  • 25. STEP 4: Check your answer Example 1: 𝒙=𝟒 𝒙=− 𝟒 Checking: For 𝒙 𝟐 −𝟏𝟔=𝟎 (𝟒)𝟐 −𝟏𝟔=𝟎 𝟏𝟔−𝟏𝟔=𝟎 𝟎=𝟎 𝒙 𝟐 −𝟏𝟔=𝟎 For (− 𝟒)𝟐 −𝟏𝟔=𝟎 𝟏𝟔−𝟏𝟔=𝟎 𝟎=𝟎 Both values of x satisfy the given equation. So, the equation is true when x = 4 or when x= -4
  • 26. Answer: The Equation has two solutions or roots: x= 4 or x= -4 Example 1:
  • 27. Example 2: 𝒙 𝟐 = 𝟎 It is already in the form of Answer: Since Property No. 3
  • 28. STEP 1: Transform the given in the form of Example 1: 𝒙 𝟐 − 𝟗=𝟎Apply Addition Property of Equality 𝒙 𝟐 −𝟗+ 𝟗=𝟎+𝟗 𝒙 𝟐 =𝟗 Or simply transpose 9 to the other side 𝒙 𝟐 =𝟗 Example 1: Example 3: 𝒙 𝟐 − 𝟗=𝟎
  • 29. STEP 2: Simplify the equation so that only the term with variable remains on the left side of that equation 𝒙 𝟐 =𝟗 Example 1: Example 1: Example 3: Answer:
  • 30. STEP 1: Transform the given in the form of Example 1: (𝒙 − 𝟒)𝟐 − 𝟐𝟓=𝟎 Apply Addition Property of Equality (𝒙 − 𝟒)𝟐 − 𝟐𝟓+𝟐𝟓=𝟎+𝟐𝟓 ( 𝒙 − 𝟒)𝟐 =𝟐𝟓 Or simply transpose -25 to the other side Example 1: Example 4: (𝒙 − 𝟒)𝟐 − 𝟐𝟓=𝟎 (𝒙 − 𝟒)𝟐 =𝟐𝟓
  • 31. STEP 3: Extract the roots of both sides of the equation √(𝒙−𝟒) 𝟐 =±√𝟐𝟓 𝒙 − 𝟒=± 𝟓 ¿ 𝒙 − 𝟒=+𝟓∧𝒙 − 𝟒=− 𝟓 Example 1: Example 1: Example 4:
  • 32. Answer: The Equation has two solutions or roots: x= 9 or x= -1 Example 4:
  • 33. SOLVE Solve the following quadratic equation by extracting the square root. Show your solutions and box your final answer. (2 points each) 6. 7. 8. 9. 10.
  • 35. Learning Objectives Identify the roots of a quadratic equations by factorising solve quadratic equation by factorising Show patience and accuracy in solving quadratic equations by factorising
  • 36. Let's Recall Solve the following equations.
  • 38. we usually use this method to solve for x when the quadratic equation is in the form: Factorisation
  • 39. Steps in Solving Quadratic Equations by Factorising 1. Write the quadratic equation in standard form. Transform the given equation in the form: 2. Factor the quadratic expression on the left side of the equation. 3. Apply the Zero Product Property by equating the two factors of quadratic equation to 0. 5. Check your answers. 4. Find the values of the variable by solving the two equations
  • 40. Zero Product Property The product AB = 0, if and only if A = 0 or B = 0.
  • 41. How to Factor Quadratic Equations When a=1
  • 42. 1. 𝑥 2 +6 𝑥 +8 =0 Examples: 3.
  • 43. Factorize the given quadratic equation x² + 6x + 8 = 0 STEP 1: Identify the values of b and c. In this example, the values of b and c are: b=6 & c=8 STEP 2: Find two numbers that both ADD to b and both MULTIPLY to c. 2 and 4 works since the sum of 2 and 4 is 6 and the product of 2 and 4 is 8 STEP 3: Use your numbers from step two to write out the factors and solve.
  • 44. Continuation Now we have a new equation: •(x+4)(x+2)=0 This is not our final answer. To solve this quadratic by factoring, we have to take each factor, set it equal to zero, and solve to find our solutions as follows: •x+4 = 0 x = -4 → •x+2 = 0 x = -2 →
  • 46. Activity Solve the following quadratic equation by factorising. Show your solutions and box your final answer. 3. 4.
  • 47. How to Factor Quadratic Equations When a≠1
  • 48. 1. 3 𝑥2 +17 𝑥 +10=0 Examples: 3. 4.
  • 49. Factorize the given quadratic equation STEP 1: Identify the values of a,b and c. In this example, the values of b and c are: a=3, b=17 & c=10 STEP 2: Multiply a and c first and then find two numbers that both ADD to b and both MULTIPLY to ac. ac = 3(10)=30. 2 and 15 works since the sum of 2 and 15 is 17 and the product of 2 and 15 is 30
  • 50. continuation STEP 3: factor and replace the middle term with the two factors ↓
  • 51. continuation STEP 4: Split the new quadratic down the middle and take the GCF of each side ↓ First Binomial: 3x² + 15x = 3x(x + 5) First Binomial: 2x + 10 = 2(x +5)
  • 52. continuation STEP 4: Identify the Factors ↓ ↓ 3x(x + 5) ↓ (3x
  • 53. Continuation Now we have a new equation: •(3x This is not our final answer. To solve this quadratic by factoring, we have to take each factor, set it equal to zero, and solve to find our solutions as follows: • 3x = 0 x = -2/3 → • = 0 x = -5 →
  • 54. Find the solution of Find the solution of 2𝑥2 + 15𝑥 = −27 Each group must pick a problem to solve and present their answer to the class. Find the solution of + 7 Find the solution of + 3 Find the solution of Find the solution of+ 5
  • 55. 1. What process are you going to use in solving quadratic equations if the given equations are in the form of ? 2. What process are you going to use in solving quadratic equations if the given equations are in the form of for a =1 and a ≠1? Generalizations: