[#443] Remove redundant Hashable constraints from intersection.*,…union.*

Data/HashMap/Internal.hs

@@ -1582,22 +1582,22 @@ submapBitmapIndexed comp !b1 !ary1 !b2 !ary2 = subsetBitmaps && go 0 0 (b1Orb2 .
 --
 -- >>> union (fromList [(1,'a'),(2,'b')]) (fromList [(2,'c'),(3,'d')])
 -- fromList [(1,'a'),(2,'b'),(3,'d')]
-union :: (Eq k, Hashable k) => HashMap k v -> HashMap k v -> HashMap k v
+union :: Eq k => HashMap k v -> HashMap k v -> HashMap k v
 union = unionWith const
 {-# INLINABLE union #-}
 
 -- | \(O(n+m)\) The union of two maps.  If a key occurs in both maps,
 -- the provided function (first argument) will be used to compute the
 -- result.
-unionWith :: (Eq k, Hashable k) => (v -> v -> v) -> HashMap k v -> HashMap k v
+unionWith :: Eq k => (v -> v -> v) -> HashMap k v -> HashMap k v
           -> HashMap k v
 unionWith f = unionWithKey (const f)
 {-# INLINE unionWith #-}
 
 -- | \(O(n+m)\) The union of two maps.  If a key occurs in both maps,
 -- the provided function (first argument) will be used to compute the
 -- result.
-unionWithKey :: (Eq k, Hashable k) => (k -> v -> v -> v) -> HashMap k v -> HashMap k v
+unionWithKey :: Eq k => (k -> v -> v -> v) -> HashMap k v -> HashMap k v
           -> HashMap k v
 unionWithKey f = go 0
   where
@@ -1718,7 +1718,7 @@ unionArrayBy f !b1 !b2 !ary1 !ary2 = A.run $ do
 -- TODO: Figure out the time complexity of 'unions'.
 
 -- | Construct a set containing all elements from a list of sets.
-unions :: (Eq k, Hashable k) => [HashMap k v] -> HashMap k v
+unions :: Eq k => [HashMap k v] -> HashMap k v
 unions = List.foldl' union empty
 {-# INLINE unions #-}
 
@@ -1833,21 +1833,21 @@ differenceWith f a b = foldlWithKey' go empty a
 
 -- | \(O(n \log m)\) Intersection of two maps. Return elements of the first
 -- map for keys existing in the second.
-intersection :: (Eq k, Hashable k) => HashMap k v -> HashMap k w -> HashMap k v
+intersection :: Eq k => HashMap k v -> HashMap k w -> HashMap k v
 intersection = Exts.inline intersectionWith const
 {-# INLINABLE intersection #-}
 
 -- | \(O(n \log m)\) Intersection of two maps. If a key occurs in both maps
 -- the provided function is used to combine the values from the two
 -- maps.
-intersectionWith :: (Eq k, Hashable k) => (v1 -> v2 -> v3) -> HashMap k v1 -> HashMap k v2 -> HashMap k v3
+intersectionWith :: Eq k => (v1 -> v2 -> v3) -> HashMap k v1 -> HashMap k v2 -> HashMap k v3
 intersectionWith f = Exts.inline intersectionWithKey $ const f
 {-# INLINABLE intersectionWith #-}
 
 -- | \(O(n \log m)\) Intersection of two maps. If a key occurs in both maps
 -- the provided function is used to combine the values from the two
 -- maps.
-intersectionWithKey :: (Eq k, Hashable k) => (k -> v1 -> v2 -> v3) -> HashMap k v1 -> HashMap k v2 -> HashMap k v3
+intersectionWithKey :: Eq k => (k -> v1 -> v2 -> v3) -> HashMap k v1 -> HashMap k v2 -> HashMap k v3
 intersectionWithKey f = intersectionWithKey# $ \k v1 v2 -> (# f k v1 v2 #)
 {-# INLINABLE intersectionWithKey #-}
 

Data/HashMap/Internal/Strict.hs

@@ -446,14 +446,14 @@ alterFEager f !k !m = (<$> f mv) $ \fres ->
 
 -- | \(O(n+m)\) The union of two maps.  If a key occurs in both maps,
 -- the provided function (first argument) will be used to compute the result.
-unionWith :: (Eq k, Hashable k) => (v -> v -> v) -> HashMap k v -> HashMap k v
+unionWith :: Eq k => (v -> v -> v) -> HashMap k v -> HashMap k v
           -> HashMap k v
 unionWith f = unionWithKey (const f)
 {-# INLINE unionWith #-}
 
 -- | \(O(n+m)\) The union of two maps.  If a key occurs in both maps,
 -- the provided function (first argument) will be used to compute the result.
-unionWithKey :: (Eq k, Hashable k) => (k -> v -> v -> v) -> HashMap k v -> HashMap k v
+unionWithKey :: Eq k => (k -> v -> v -> v) -> HashMap k v -> HashMap k v
           -> HashMap k v
 unionWithKey f = go 0
   where
@@ -622,15 +622,15 @@ differenceWith f a b = HM.foldlWithKey' go HM.empty a
 -- | \(O(n+m)\) Intersection of two maps. If a key occurs in both maps
 -- the provided function is used to combine the values from the two
 -- maps.
-intersectionWith :: (Eq k, Hashable k) => (v1 -> v2 -> v3) -> HashMap k v1
+intersectionWith :: Eq k => (v1 -> v2 -> v3) -> HashMap k v1
                  -> HashMap k v2 -> HashMap k v3
 intersectionWith f = Exts.inline intersectionWithKey $ const f
 {-# INLINABLE intersectionWith #-}
 
 -- | \(O(n+m)\) Intersection of two maps. If a key occurs in both maps
 -- the provided function is used to combine the values from the two
 -- maps.
-intersectionWithKey :: (Eq k, Hashable k) => (k -> v1 -> v2 -> v3)
+intersectionWithKey :: Eq k => (k -> v1 -> v2 -> v3)
                     -> HashMap k v1 -> HashMap k v2 -> HashMap k v3
 intersectionWithKey f = HM.intersectionWithKey# $ \k v1 v2 -> let !v3 = f k v1 v2 in (# v3 #)
 {-# INLINABLE intersectionWithKey #-}

Data/HashSet/Internal.hs

@@ -306,14 +306,14 @@ isSubsetOf s1 s2 = H.isSubmapOfBy (\_ _ -> True) (asMap s1) (asMap s2)
 --
 -- >>> union (fromList [1,2]) (fromList [2,3])
 -- fromList [1,2,3]
-union :: (Eq a, Hashable a) => HashSet a -> HashSet a -> HashSet a
+union :: Eq a => HashSet a -> HashSet a -> HashSet a
 union s1 s2 = HashSet $ H.union (asMap s1) (asMap s2)
 {-# INLINE union #-}
 
 -- TODO: Figure out the time complexity of 'unions'.
 
 -- | Construct a set containing all elements from a list of sets.
-unions :: (Eq a, Hashable a) => [HashSet a] -> HashSet a
+unions :: Eq a => [HashSet a] -> HashSet a
 unions = List.foldl' union empty
 {-# INLINE unions #-}
 
@@ -391,7 +391,7 @@ difference (HashSet a) (HashSet b) = HashSet (H.difference a b)
 --
 -- >>> HashSet.intersection (HashSet.fromList [1,2,3]) (HashSet.fromList [2,3,4])
 -- fromList [2,3]
-intersection :: (Eq a, Hashable a) => HashSet a -> HashSet a -> HashSet a
+intersection :: Eq a => HashSet a -> HashSet a -> HashSet a
 intersection (HashSet a) (HashSet b) = HashSet (H.intersection a b)
 {-# INLINABLE intersection #-}